我正在使用下面的代码片段在Python中编写HTTP服务器。服务器运行良好,直到发生一些IOError导致它重新启动。由于服务器启动正常,但重新启动处理出错,但之后不接受任何请求。在Python中重新启动HTTP服务器的正确方法
这段代码有什么问题吗?
#!/bin/python
from BaseHTTPServer import HTTPServer
import json
import config
import time
import socket
from SimpleHTTPServer import SimpleHTTPRequestHandler
from SocketServer import BaseServer
class MyHandler(SimpleHTTPRequestHandler):
def parseArgs(self):
args = {}
try:
config.logging.info(self.path)
args_list = self.path.split("?")[1].split("&")
for entry in args_list:
args[entry.split("=")[0]] = entry.split("=")[1]
except IndexError:
pass
return args
def do_GET(self):
try:
response = {}
args = self.parseArgs()
config.logging.debug("Handle the request")
self._handle_request(args, response)
config.logging.debug("Write the header back to the client.")
self.send_response(200)
self.send_header('Access-Control-Allow-Origin', '*')
self.send_header('Content-Type:', 'application/json; charset=UTF-8')
self.end_headers()
config.logging.debug("Finish writing the header and start writing JSON response.")
json_encoded = json.dumps(response)
config.logging.debug(json_encoded)
self.wfile.write(json_encoded)
config.logging.debug("JSON Response written successfully.")
except Exception as e:
config.logging.exception('Exception occurs when writing back the response.')
return
def _handle_request(self, args, response):
try:
response["sysTime"] = long(round(time.time() * 1000))
if not "cmd" in args:
response["message"] = "Error: No command provided."
else:
response["message"] = args['cmd']
except Exception as e:
response["message"] = "Error: Exception occurs (check logs)."
config.logging.exception('Exception occurs when handling request.')
def do_POST(self):
self.send_response(200)
self.send_header('Content-type', 'text/html')
self.end_headers()
self.wfile.write("Nothing here :(")
def main():
while True:
try:
httpd = HTTPServer(('', config.listening_port), MyHandler)
sa = httpd.socket.getsockname()
msg = "Serving HTTP on " + sa[0] + " port " + str(sa[1]) + "..."
print msg
config.logging.info(msg)
httpd.serve_forever()
except KeyboardInterrupt:
print '^C received, shutting down server'
config.logging.info('^C received, shutting down server')
httpd.socket.close()
break
except Exception as e:
httpd.shutdown()
httpd.socket.close()
print "Error occurs. Retry in 5 seconds"
config.logging.exception('Exception occurs. Retry in 5 seconds.')
time.sleep(5)
if __name__ == '__main__':
main()
对不起,错过了模块配置。
import logging
# global variables
listening_port = 9001
logging.basicConfig(filename='error.log', level=logging.INFO, format='%(asctime)s - %(levelname)s - %(message)s', datefmt='%m/%d/%Y %I:%M:%S %p')
运行此操作的一个网址是http://localhost:9001/?cmd=some_command
。只需在服务器启动后将其粘贴到任何浏览器中即可。
编辑:
我想这事做与KVM或它被设定为我公司的机器上的方式。由于我的服务器运行在只能通过ssh访问的KVM上,每次退出ssh会话时,调用上面的url命令(在chrome中),等到chrome通知没有连接,返回到ssh会话,调用url再次发出命令,错误发生了。
我把调试消息放在do_GET()中的写入响应之间self.send_response(200)
。当发生异常时,这是我得到的踪迹。我猜这跟log_message里面的sys.stderr.write
有关。
11/23/2012 10:58:29 AM - INFO - Handle the request
11/23/2012 10:58:29 AM - INFO - /?cmd=get_info&uid=pp
11/23/2012 10:58:29 AM - INFO - Write the header back to the client.
11/23/2012 10:58:29 AM - ERROR - Exception occurs when writing back the response.
Traceback (most recent call last):
File "service.py", line 57, in do_GET
self.send_response(200)
File "/usr/lib/python2.7/BaseHTTPServer.py", line 385, in send_response
self.log_request(code)
File "/usr/lib/python2.7/BaseHTTPServer.py", line 422, in log_request
self.requestline, str(code), str(size))
File "/usr/lib/python2.7/BaseHTTPServer.py", line 458, in log_message
format%args))
IOError: [Errno 5] Input/output error
编辑:
问题就走了,当我重写log_message()
什么也不做。我知道这只是隐藏了问题,但至少它暂时对我有用。
你有没有考虑过使用[Flask](http://flask.pocoo.org/)?那么你不必担心这些东西...... –
或[gunicorn](http://gunicorn.org/)。 – syrion
当我尝试它时,您的代码有效:服务器在5秒后重新启动并再次接受连接。但是为了伪造失败,我不得不破解SocketServer.py,因为我无法从serve_forever()中获得异常。你需要发布一个让我们先重现问题的例子。 –