MySQL查询只选择日期

组的最后一排，我有以下查询：MySQL查询只选择日期

SELECT ELO，日期（date_calculated）日期从users_historical_elo其中uid = 36 ORDER BY ID ASC

产生这样的结果：

| elo | date

|984|2011-04-04

|1010|2011-04-04

|1036|2011-04-04

|1016|2011-04-08

|1000|2011-04-08

|944|2011-04-09

|973|2011-04-09

...

我需要帮助编写一个查询，按日期只选择最后一个“elo”分组。所以输出应该是：

| elo | date

|1036|2011-04-04

|1000|2011-04-08

|973|2011-04-09

...

谢谢！

来源

2011-05-29 newyuppie

你的意思'| 1016 | 2011-04-08'，对不对？ – 2011-05-29 01:00:09

哦，对不起，你有'按ID订购'，好。 – 2011-05-29 01:01:44

http://stackoverflow.com/questions/3449757/sql-group-by-records-and-then-get-last-record-from-each-group – NAVEED 2011-05-29 01:09:23

如果id是表的主键，那么这将做到：

SELECT elo 
    , date(date_calculated) AS date 
FROM users_historical_elo 
    JOIN 
    (SELECT MAX(id) AS id 
     FROM users_historical_elo 
     WHERE uid =36 
     GROUP BY date(date_calculated) 
    ) AS grp 
    ON grp.id = users_historical_elo.id 
ORDER BY grp.id ASC

来源

2011-05-29 01:05:48

它完美的工作，谢谢 – newyuppie 2011-05-29 02:43:54

道德的额外信贷;）如果我有相同的情况，我怎么能修改这个查询，但我需要选择按日期分组的*倒数第二个* elo？ – newyuppie 2011-05-29 21:01:05

尝试：

SELECT elo, date(date_calculated) date FROM users_historical_elo WHERE uid =36 group by date order by id asc

来源

2011-05-29 01:02:49 kevinAlbs

我认为你需要使用MAX和GROUP BY。见http://www.tutorialspoint.com/mysql/mysql-max-function.htm

我认为这会工作

SELECT elo, MAX(date(date_calculated)) date 
FROM users_historical_elo 
WHERE uid =36 
GROUP BY elo 
ORDER BY id asc

来源

2011-05-29 01:03:27 cordsen

此：

SELECT elo, MAX(date) FROM users_historical_elo

将返回ELO和任何ELO，这似乎是你所要求的最后日期？

来源

2011-05-29 01:04:22 Rob

MySQL查询只选择日期

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