POSTGRESQL - 错误的返回select查询

这里是我的功能，执行此功能时，它会返回错误：POSTGRESQL - 错误的返回select查询

create or replace function country(varchar) 

returns customer(customer_id integer, 
       first_name varchar,      
        last_name varchar) as $$ 


select customer_id, customer.first_name, customer.last_name 

from customer 

    inner join address on customer.address_id = address.address_id 
    inner join city on address.city_id = city.city_id 
    inner join country on city.country_id = country.country_id 

where country = '$1'; 

$$ 
language sql;

错误返回查询发生。

来源

2016-12-22 kimdasuncion12

我认为你有一个错字，你应该使用'哪里国家= $ 1'，_没有单引号。 –

你有什么错误？ – Mureinik

错误：在“整数”处或附近的语法错误 LINE 2：返回customer（customer_id integer，谢谢Tim我删除了单引号，但这个错误表明我说有语法错误，并指出整数可以帮助我进出口新的Postgres的 – kimdasuncion12

使用创建此解决方案类型：

create type ct as (customer_id integer, first_name varchar, last_name varchar)

现在创建功能

create or replace function country(varchar) 

returns ct as $$ 

select customer_id, first_name, last_name from customer 
    inner join address on customer.address_id = address.address_id 
    inner join city on address.city_id = city.city_id 
    inner join country on city.country_id = country.country_id  
where country = $1; 

$$ language sql;

或使用本

create or replace function country(varchar) 

returns table(customer_id integer, 
       first_name varchar,      
        last_name varchar) as $$ 

select customer_id, customer.first_name, customer.last_name 

from customer 

    inner join address on customer.address_id = address.address_id 
    inner join city on address.city_id = city.city_id 
    inner join country on city.country_id = country.country_id 

where country = $1; 

$$language sql;

来源

2016-12-22 06:11:23

谢谢萨达姆我用你的编辑功能，但现在它返回<不愿透露姓名的门户网站1>。 – kimdasuncion12

dvdrental =＃选择国家（'阿尔及利亚'）; 国家 -------------------- <无名门户6> （1行）这就是我得到的结果 – kimdasuncion12

你在使用光标吗？你正在使用1或2（我写上面） –

POSTGRESQL - 错误的返回select查询

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