如何解析XML文件并在Java中检查每个元素是否有子元素？

Question

我有一个XML文件，如下图所示：

<customers> 
    <customer> 
     <name>XXX</name> 
     <address>Nagar</address> 
     <number> 
      <num1>123</num1> 
      <num2>456</num2> 
     </number> 
    </customer> 
    <customer> 
     <name>YYY</name> 
     <address>Nagar</address> 
     <number> 
      <num1>789</num1> 
      <num2>012</num2> 
     </number> 
    </customer> 
</customers> 

我需要解析从上到下整个XML，并得到每个元素的子节点的信息。

例外输出：（节点=孩子）

customers = customer,customer 
customer = name,address,number 
name = null 
address = null 
number = num1,num2 
num1 = null 
num2 = null 
customer = name,address,number 
name = null 
address = null 
number = num1,num2 
num1 = null 
num2 = null 

我用DOM此。下面给出的代码：

NodeList nodeList = doc.getElementsByTagName("*"); 
for (int i = 0; i < nodeList.getLength(); i++) { 
Node node = nodeList.item(i); 
    if (node.getNodeType() == Node.ELEMENT_NODE) { 
     System.out.println(node.getNodeName()+" = "+node.getChildNodes()); 
    } 
} 

但我得到的输出是这样的：

customers = [customers: null] 
customer = [customer: null] 
name = [name: null] 
address = [address: null] 
number = [number: null] 
num1 = [num1: null] 
num2 = [num2: null] 
customer = [customer: null] 
name = [name: null] 
address = [address: null] 
number = [number: null] 
num1 = [num1: null] 
num2 = [num2: null] 

能否请你帮我这个。

Answer 1

您需要另一个循环在循环，通过孩子

这工作遍历：

NodeList nodeList = document.getElementsByTagName("*"); 
for (int i = 0; i < nodeList.getLength(); i++) 
    { 
    Node node = nodeList.item(i); 
    if (node.getNodeType() == Node.ELEMENT_NODE) 
     { 
     Element element=(Element) node; 

     System.out.print(element.getNodeName()+" = "); 
     boolean is_first_child=true; 

     // CHILDS 
     NodeList nodechilds=node.getChildNodes(); 

     for (int j = 0; j < nodechilds.getLength(); j++) 
      { 
      Node a_child = nodechilds.item(j); 

      if (a_child.getNodeType() == Node.ELEMENT_NODE) 
       { 
       if (!is_first_child) System.out.print (","); 
       System.out.print (a_child.getNodeName()); 

       is_first_child=false; 
       } 
      } 

    if (is_first_child) System.out.print ("null"); 
    System.out.println(); 
    } 
}