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因此,即时通讯这一奋斗2天,我还没有看到谷歌的任何例如有关,它的作品,所以我想它不工作是这样的:插入MySQL数据库其中username =:用户名
$steamusername = "xx";
$uname = $_SESSION['username'];
$sql1 = "INSERT INTO users (steamusername) VALUES (:steamusername) WHERE :username = username";
$query = $conn->prepare($sql1);
$result = $query->execute(array(':steamusername'=>$steamusername, ':username'=>$uname));
它不会给出任何错误,但它也不会将其放入数据库中。
我真的不知道我怎么可以让它它进入用户表,我也试图更新字段:
$sql1 = "UPDATE users SET steamusername = :steamusername WHERE username = :username";
$stmt1 = $conn->prepare($sql1);
$stmt1->bindParam(':username', $uname);
$stmt1->bindValue(':steamusername', $steamusername);
$stmt1->execute();
有谁知道解决的办法?提前致谢!
想想INSERT .... WHERE以及如何工作 – Mihai
其实它可能会给出错误。你不知道,因为你没有检查一个。尝试'if(!($ stmt1 = $ conn-> prepare($ sql1))){throw new Exception($ stmt1-> error); }'和'if($ stmt1-> execute()){抛出新的异常($ stmt1-> error); }' – OscarJ