如何合并两个词典与Python中的字典？

Question

下面是来自类似输入的大文件的示例输入。

{ 
    "V-Su7890": [ 
     [ 
      { 
       "url": "www.talent.com", 
       "tid": "V-Su7890", 
       "id": "58ff787ffbad487b2c", 
       "company_name": "Talent Ltd" 
      } 
     ], 
     [ 
      { 
       "socials": ["facebook", "linkedin", "twitter"], 
       "title": "title of the pag", 
       "contact": ["+9563802140"], 
       "email": "email_id1" 
      }, 
      { 
       "socials": ["facebook", "twitter", "linkedin"], 
       "title": "next title of the page", 
       "contact": ["+919765983442"], 
       "email": "email_id2" 
      } 
     ] 
    ] 
} 

我不得不当前词典的第二列表的所有分字典合并成一个字典没有重复的值，然后存入字典作为一个值键“V-Su7890”。

所需的输出是：

{ 
    "V-Su7890": [ 
     [ 
      { 
       "url": "www.talent.com", 
       "tid": "V-Su7890", 
       "id": "58ff787ffbad487b2c", 
       "company_name": "Talent Ltd" 
      } 
     ], 
     [ 
      { 
       "socials": ["facebook", "linkedin", "twitter"], 
       "title": ["title of the pag", "next title of the page"], 
       "contact": ["+9563802140", "+919765983442"], 
       "email": ["email_id","email_id2"] 
      } 
     ] 
    ] 
} 

请帮助我了解和解决这个问题。

Answer 1

您可以使用setdefault()以默认值插入关键（在这里你可以使用空表），并extend列表，如果新项目不存在。

for k,v in a.items(): 
    tmp={} 
    for i in v[1]: 
     for k1,v2 in i.items(): 
      if isinstance(v2,list): 
       tmp.setdefault(k1,[]).extend(i for i in v2 if i not in tmp[k1]) 
      else: 
       tmp.setdefault(k1,[]).append(v2) 
    a[k]=[v[0],[tmp]] 
print(a) 

结果：

{ 
    'V-Su7890': [ 
    ... 
    [ 
     { 
     'contact': ['+9563802140','+919765983442'], 
     'socials': ['facebook','linkedin','twitter'], 
     'email': ['email_id1','email_id2'], 
     'title': ['title of the pag','next title of the page'] 
     } 
    ] 
    ] 
} 

Answer 2

假设你存储完整dict在一个变量V.我们为socials，title等存储在一组值，以避免出现重复的值。稍后，我们会将这些设置转换为列表。这里的解决方案：

V = k["V-Su7890"][1] 
new_dict = {} 

for v in V: 
    for key, value in v.iteritems(): 
     if not new_dict.get(key, None): 
      new_dict[key] = set() 

     if isinstance(value, list): 
      for val in value: 
       new_dict[key].add(val) 
     else: 
      new_dict[key].add(value) 

# Converting the sets to list 
for key, value in new_dict.iteritems(): 
    new_dict[key] = list(value) 

k["V-Su7890"][1] = [new_dict]