urllib的HTTP错误403

Question

我已经通过了论坛搜索，试图找出为什么下面的代码不工作：

import nltk, re, pprint 
from urllib import request 
url = "http://www.gutenberg.org/files/2554/2554.txt" 
response = request.urlopen(url) 
raw = response.read().decode('utf8') 
print(raw[:75]) 

但迄今为止，已经解决的事情不成功。这里有一些类似的解决方案，我试图执行无济于事： Forum 1, Forum 2

我得到的错误是：

File "C:\Python33\lib\urllib\request.py", line 163, in urlopen 
return opener.open(url, data, timeout) 
File "C:\Python33\lib\urllib\request.py", line 472, in open 
response = meth(req, response) 
File "C:\Python33\lib\urllib\request.py", line 582, in http_response 
'http', request, response, code, msg, hdrs) 
File "C:\Python33\lib\urllib\request.py", line 510, in error 
return self._call_chain(*args) 
File "C:\Python33\lib\urllib\request.py", line 444, in _call_chain 
result = func(*args) 
File "C:\Python33\lib\urllib\request.py", line 590, in http_error_default 
raise HTTPError(req.full_url, code, msg, hdrs, fp) 
urllib.error.HTTPError: HTTP Error 403: Forbidden 

任何帮助，将不胜感激

Answer 1

此代码：

Python 2

from urllib import urlopen 

url = "http://www.gutenberg.org/files/2554/2554.txt" 
response = urlopen(url) 

if response.code == 200: 
    raw = response.read().decode('utf-8') 
    print raw[:75] 
else: 
    print 'Error', response.code 

response.close() 

响应：

The Project Gutenberg EBook of Crime and Punishment, by Fyodor Dostoevsky

的Python 3

from urllib import request 

url = "http://www.gutenberg.org/files/2554/2554.txt" 

try: 
    response = request.urlopen(url) 
    raw = response.read().decode('utf-8') 
    print(raw[:75]) 
except Exception as ex: 
    print('Error:', ex) 

如果得到HTTP代码403，这意味着你访问这个网址被禁止。