搜索SQL查询这是真的

Question

我有一个很好的搜索查询，但我需要它只显示结果visible = true。这就是需要添加到查询中，我只是不知道如何正确执行。这是查询。

$查询= $ mysqli->查询（“选择 ID，姓名，公司，城市FROM人WHERE 名LIKE '％$ mysearchString％' OR 公司LIKE '％$ mysearchString％' OR 镇LIKE'％$ mysearchString％'ORDER BY name DESC LIMIT 100“）;

$ mysearchString var只是一个消毒过的$_GET['s']。

Answer 1

SELECT id,name,company,town 
FROM people WHERE 
(name LIKE '%$mysearchString%' 
OR company LIKE '%$mysearchString%' 
OR town LIKE '%$mysearchString%') 
AND visible = true 
ORDER BY name DESC LIMIT 100 

Answer 2

$query = $mysqli->query("SELECT id,name,company,town FROM people WHERE (name LIKE '%$mysearchString%' OR company LIKE '%$mysearchString%' OR town LIKE '%$mysearchString%') AND visible = true ORDER BY name DESC LIMIT 100");