创建使用PHP

Question

我有这个迄今为止JSON输出：

if (is_request_var('requestor') == 'PPA'){ 
    $dataJson[][] = array("status" => "success","value" => $fetchValue ,"postcode" => $fetchPostCode,"params"=>""); 

    $notice = $dataJson; 
} 

我想从PHP（如下所述）我如何安排我的PHP阵列码

jQuery191013316784294951245_1485527378760([ 
    { 
    "value": "\u003cstrong\u003eNAIROBI\u003c/strong\u003e KENYATTA AVENUE, GENERAL POST OFFICE, 00100", 
    "postcode": "00100" 
    }, 
    { 
    "value": "\u003cstrong\u003eNAIROBI\u003c/strong\u003e HAILE SALASSIE AVENUE, CITY SQUARE, QLD, 00200", 
    "postcode": "00200" 
    } 
]) 

Answer 1

试试这个：

$dataJson = array("value" => $fetchValue, "postcode" => $fetchPostCode); 
$notice = json_encode($dataJson); 
echo $notice; 

返回包含值的JSON表示的字符串。

http://php.net/manual/en/function.json-encode.php