Mysql选择匹配4,5或6列

Question

我正在对具有6个不同列的数据库进行自定义搜索。 为了使搜索我有6个不同的输入字段，只接受数字。

我已经拿到了6列搜查工作，代码：

SELECT * FROM data 
WHERE 1_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') 
AND 2_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') 
AND 3_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') 
AND 4_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') 
AND 5_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') 
AND 6_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') 
ORDER BY id ASC; 

这使得尽管输入的顺序正确的结果。

但我需要选择给我的结果，无论它发现匹配输入的数字4或5。我尝试了OR，但我不知道如何定义匹配的列的数量。

这可能吗？

感谢您的关注！

编辑：-------------------

我被困与dbaseman提供的代码。

因为我得到了一个真实的结果，但我真的不知道它是否是通过匹配4,5或6列产生的。

我期待插入CASE WHEN后，但不工作。

有没有办法知道列的哪个组合给了我结果？

想到类似于（粗略）if = 4，then result-4，else if = 5，then result-5 ... etc ... 然后就可以将该行放入数组中。

谢谢！

Answer 1

而不是使用和/或总结命中：

SELECT *, 
    CASE WHEN 1_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END AS match_1, 
    CASE WHEN 2_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END AS match_2, 
    CASE WHEN 3_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END AS match_3, 
    CASE WHEN 4_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END AS match_4, 
    CASE WHEN 5_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END AS match_5, 
    CASE WHEN 6_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END AS match_6, 

    CASE WHEN 1_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END 
    + CASE WHEN 2_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END 
    + CASE WHEN 3_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END 
    + CASE WHEN 4_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END 
    + CASE WHEN 5_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END 
    + CASE WHEN 6_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END 
    AS no_of_matches 
FROM data 
WHERE 
    (
    CASE WHEN 1_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END 
    + CASE WHEN 2_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END 
    + CASE WHEN 3_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END 
    + CASE WHEN 4_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END 
    + CASE WHEN 5_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END 
    + CASE WHEN 6_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END 
    ) in (4,5,6) 
ORDER BY id ASC; 

备用，使用嵌套查询了一下漂亮：

SELECT a.*, a.match_1+a.match_2+a.match_3+a.match_4+a.match_5+a.match_6 AS no_of_matches 
FROM (
    SELECT *, 
     CASE WHEN 1_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END AS match_1, 
     CASE WHEN 2_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END AS match_2, 
     CASE WHEN 3_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END AS match_3, 
     CASE WHEN 4_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END AS match_4, 
     CASE WHEN 5_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END AS match_5, 
     CASE WHEN 6_column IN ('$a1a','$a2a','$a3a','$a4a','$a5a','$a6a') THEN 1 ELSE 0 END AS match_6 
     FROM data 
    ) a 
WHERE a.match_1+a.match_2+a.match_3+a.match_4+a.match_5+a.match_6 in (4,5,6) 
ORDER BY id ASC;