如何在iPhone的NSString中获取并获取URL？

Question

我在http：//在NSString中有一个文本。我想从NSString获取该链接。我怎么能从字符串中获得链接/网址？例如：'叠加流程对于初学者https://stackoverflow.com/'非常有用。我想从文本中获得'https://stackoverflow.com/'。我怎样才能做到这一点？提前致谢。

Answer 1

我不知道你到底是通过链接的意思，但如果你想你的NSString转换为NSURL比你可以做到以下几点：

NSString *urlString = @"http://somepage.com"; 
NSURL *url = [NSURL URLWithString:urlString]; 

编辑

这是怎么弄在给定的NSString所有网址：

NSString *str = @"This is a grate website http://xxx.xxx/xxx you must check it out"; 

NSArray *arrString = [str componentsSeparatedByString:@" "]; 

for(int i=0; i<arrString.count;i++){ 
    if([[arrString objectAtIndex:i] rangeOfString:@"http://"].location != NSNotFound) 
     NSLog(@"%@", [arrString objectAtIndex:i]); 
} 

Answer 2

试试这个：

nsstring *str = @"Stack over flow is very useful link for the beginners http://stackoverflow.com/"; 

nsstring *http = @"http"; 
nsarray *arrURL = [str componentsSeparatedByString:@"http"]; 

这会在nsarray中给出两个对象。第一个对象将是具有：Stack over flow is very useful link for the beginners和2将是：://stackoverflow.com/（我猜）

，那么你可以这样做：

NSString *u = [arrURL lastObject]; 

那么就喜欢：

nsstring *http = [http stringByAppendingFormat:@"%@",u]; 

相当漫长的，但我认为这会对你有用。希望能帮助你。

Answer 3

而不是分裂的字符串到一个数组，折腾了这种方式，你可以搜索字符串以@开头的“http：//”：

NSString *str = @"Stack over flow is very useful link for the beginners http://stackoverflow.com/"; 
// get the range of the substring starting with @"http://" 
NSRange rng = [str rangeOfString:@"http://" options:NSCaseInsensitiveSearch]; 

// Set up the NSURL variable to hold the created URL 
NSURL *newURL = nil; 

// Make sure that we actually have found the substring 
if (rng.location == NSNotFound) { 
    NSLog(@"URL not found"); 
    // newURL is initialised to nil already so nothing more to do. 
} else { 
    // Get the substring from the start of the found substring to the end. 
    NSString *urlString = [str substringFromIndex:rng.location]; 

    // Turn the string into an URL and put it into the declared variable 
    newURL = [NSURL URLWithString:urlString]; 
}