我想运行一个更新,它基于多个变量分配一个varchar数据块。这里有一个例子我的SQL代码:更新mysql和设置信息块
'update details set full = "Miles reported by $name - $empname - $deptname\n\n"
"Total Miles in $month: $dailytotal\n"
"Total Business Miles in $month: $busitotal\n"
"Total Personal Miles in $month: $perstotal\n\n"
"$month 1: START: $start1...STOP: $stop1...DAILY: $daily1...BUSINESS: $busi1...PERSONAL: $personal1\n"
"$month 2: START: $start2...STOP: $stop2...DAILY: $daily2...BUSINESS: $busi2...PERSONAL: $personal2\n"
')
or die "Could not prepare sql statement";
工作正常和所有,但问题是它的存储变量为“$名”,而不是什么$ name是连同所有其他变量相同。我怎样才能解决这个问题,并对我的格式感到抱歉。提前致谢!
谢谢你,这真的帮助我,我也欣赏额外的文件。 – BluGeni