虽然循环不打印正确的猜字游戏

Question

如何让循环工作，以便它会在你正确的时候结束并且如果你弄错了再问这个问题？ 当我猜错两次或更多次时，无论发生什么事，总会说错。

import random; 
import sys; 
x = random.randint(1, 100); 
print(x); 
guess = int(input("Guess a number 1 to 100")); 
if guess == x: 
     print("correct"); 
     sys.exit() 
while guess != x: 
    print("wrong"); 
    int(input("Guess a number 1 to 100")); 
    print(x); 
    if guess == x: 
     print("Correct"); 
     sys.exit() 

另外什么函数记录它循环的次数。例如，如果我猜错了10次，然后我要打印，我打进了10

Answer 1

你忘了周围的分配，第二次在该guess变量

while guess != x: 
    print("wrong"); 
    guess = int(input("Guess a number 1 to 100")); #look here 
    print(x); 
    if guess == x: 
     print("Correct"); 
     sys.exit() 

Answer 2

失踪“的猜测=”循环中的输入行。要记录次数，只需在循环中增加一个变量即可。

[附录]

import random; 
import sys; 
x = random.randint(1, 100); 
print(x); 
count = 1 
guess = int(input("Guess a number 1 to 100: ")); 
while guess != x: 
    count += 1 
    guess = int(input("Wrong\nGuess a number 1 to 100: ")); 
print("Correct - score = "+str(100./count)+"%"); 
sys.exit(0) 

Answer 3

其实你应该改变你的代码：

import random 
x=random.randint(1,100) 
score=0 
while True: 
    guess=int(input("Guess a number 1 to 100: ")) 
    if guess==x: 
     print ("Correct!") 
     break 
    else: 
     print ("Not correct!") 
     score+=1 
print ("your answers was wrong {} times.".format(score)) 

更好的语句，少的代码。干杯!