推导开始和结束日期从日期范围内特定记录

Question

使用SQL Server 2008

我有一个创纪录的数字，并与“中”和列“出”的数据与相关的一些日期它。 我想根据标准推导出他们的开始日期和结束日期。最短日期成为开始日期，紧接着的下一个日期成为结束日期。一个记录可以有多个输入和输出。以下是一些示例查询，尝试了几个选项但没有任何成效。

IF OBJECT_ID('tempdb..#tmp_Info') IS NOT NULL DROP TABLE #tmp_Info 
IF OBJECT_ID('tempdb..#RN') IS NOT NULL DROP TABLE #RN 

CREATE TABLE #tmp_Info 
(
RECORD_NO   INT, 
TYPE_1   VARCHAR(10), 
TYPE_2   VARCHAR(250), 
START_END   DATE 
) 


INSERT INTO #tmp_Info (RECORD_NO, TYPE_1, TYPE_2, START_END) 

VALUES 
(261505,'IN','ADM','1/1/2001'), 
(261505,'OUT','RELEASE','2/6/2001'), 
(261505,'IN','ADM','2/10/2001'), 
(261505,'OUT','RELEASE','4/2/2001'), 
(261505,'IN','ADM','5/12/2001'), 
(261505,'OUT','RELEASE','7/13/2001'), 
(261506,'IN','ADM','1/12/2001'), 
(261506,'OUT','RELEASE','2/15/2001'), 
(261506,'IN','ADM','2/20/2001'), 
(261506,'OUT','RELEASE','4/2/2001'), 
(261506,'IN','ADM','5/15/2001'), 
(261506,'OUT','RELEASE','7/17/2001'), 
(261506,'IN','ADM','8/1/2001') 

SELECT * FROM #tmp_Info; 

-->>>> OPTION 1 
WITH STARTEND AS 
(
SELECT T.RECORD_NO, T.START_END, RN = ROW_NUMBER() OVER (PARTITION BY RECORD_NO, TYPE_1 ORDER BY START_END) 
FROM #tmp_Info T 
) 
SELECT A.RECORD_NO,A.START_END AS START_DT, B.START_END AS END_DT 
FROM STARTEND A 
LEFT JOIN STARTEND B ON A.RECORD_NO = B.RECORD_NO AND A.RN = B.RN+1 
ORDER BY A.RECORD_NO, A.START_END; 

-->>>>OPTION 2 

SELECT T.*, RN = ROW_NUMBER() OVER (PARTITION BY RECORD_NO, TYPE_1 ORDER BY START_END) 
into #RN 
FROM #tmp_Info T 

SELECT * FROM #RN 

我附上结果集我要找：

Answer 1

您可以使用下面的查询：

;WITH CTE_Rn AS (
    SELECT RECORD_NO, TYPE_1, TYPE_2, START_END, 
      ROW_NUMBER() OVER (PARTITION BY RECORD_NO, TYPE_1 
          ORDER BY START_END) AS rn 
    FROM #tmp_Info 
) 
SELECT t1.RECORD_NO, t1.START_END AS START_DT, t2.START_END AS END_DT   
FROM CTE_Rn AS t1 
LEFT JOIN CTE_Rn AS t2 
ON t1.RECORD_NO = t2.RECORD_NO AND  
    t2.TYPE_1 = 'OUT' AND 
    t1.rn = t2.rn 
WHERE t1.TYPE_1 = 'IN';