Mysql的复杂排序

我有这样Mysql的复杂排序

SELECT videos.*, 
     (SELECT COUNT(comment_id) 
     FROM comments 
     WHERE comments.comments_video_id = videos.id) AS video_comments 
FROM videos 
ORDER BY video_comments DESC

查询现在，如果我有2行以同样“videos_comments”计数，怎么可以这样写，这样这两个视频之间的一个其中有最新的评论（comments_date）在意见表显示第一

来源

2016-01-21 fredmarks

只需在带有DESC的ORDER BY中使用comment_Date，并且还可以在GROUP中使用comment_date，这样您将只通过comment_date获得一条记录 –

@GaganUpadhyay感谢您的快速回复，任何示例代码的机会，我相当新MySQL的 – fredmarks

SELECT videos.id, count(*) video_comments 
FROM videos LEFT JOIN comments 
ON comments.comments_video_id = videos.id 
GROUP BY videos.id 
ORDER BY video_comments DESC

来源

2016-01-21 05:17:58 SIDU

SELECT videos.id, 
     MAX(comments_date) as latest_comment, 
     COUNT(*) as video_comments 
FROM videos 
LEFT JOIN comments 
     ON comments.comments_video_id = videos.id 
GROUP BY videos.id 
ORDER BY 
     video_comments, 
     latest_comment

如果你想要的视频。*

SELECT videos.*, 
     video_comments, 
     latest_comment 
FROM videos 
JOIN (
     SELECT videos.id, 
       MAX(comments_date) as latest_comment, 
       COUNT(*) as video_comments 
     FROM videos 
     LEFT JOIN comments 
       ON comments.comments_video_id = videos.id 
     GROUP BY videos.id 

    ) T 
    ON videos.video_id = T.video_id 
ORDER BY 
     video_comments, 
     latest_comment

来源

2016-01-21 05:29:53

Mysql的复杂排序

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