无法获取SQLite的删除记录

-1

我有高分游戏，我试图删除得分最低。除了我的应用程序崩溃时，我的deleteProduct（）方法被调用时，一切正常。 Logcat说这是一个语法错误，但我真的不知道什么是错误的，因为这是我的第一个SQLite应用程序。无法获取SQLite的删除记录

public class MyDBHandler extends SQLiteOpenHelper { 

private static final int DATABASE_VERSION = 4; 
private static final String DATABASE_NAME = "products.db"; 
public static final String TABLE_PRODUCTS = "products"; 
public static final String COLUMN_ID = "_id"; 
public static final String COLUMN_PRODUCTNAME = "productname"; 

public MyDBHandler(Context context, String name, SQLiteDatabase.CursorFactory factory, int version) { 
    super(context, DATABASE_NAME, factory, DATABASE_VERSION); 
} 


@Override 
public void onCreate(SQLiteDatabase db) { 
    String query = "CREATE TABLE " + TABLE_PRODUCTS + "(" + 
      COLUMN_ID + " INTEGER PRIMARY KEY AUTOINCREMENT, " + 
      COLUMN_PRODUCTNAME + " TEXT " + 
      ");"; 
    db.execSQL(query); 
} 

@Override 
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) { 
    db.execSQL("DROP TABLE IF EXISTS " + TABLE_PRODUCTS); 
    onCreate(db); 
} 

//add a new row to the database 
public void addProduct(Products product){ 

    SQLiteDatabase db = this.getReadableDatabase(); 
    if(DatabaseUtils.queryNumEntries(db, TABLE_PRODUCTS) <= 4){ 
     ContentValues values = new ContentValues(); 
     values.put(COLUMN_PRODUCTNAME, product.get_productname()); 
     db.insert(TABLE_PRODUCTS, null, values); 
     db.close(); 
    } 
    else if((!(DatabaseUtils.queryNumEntries(db, TABLE_PRODUCTS) <= 4)) /*&& new score is a highscore */){ 
     //how to insert new high score into correct spot and delete last high score 
     ContentValues values = new ContentValues(); 
     values.put(COLUMN_PRODUCTNAME, product.get_productname()); 
     db.insert(TABLE_PRODUCTS, null, values); 
     deleteProduct(); 
     db.close(); 

    } 
} 

//code coming from MainActivity 
public void addButtonClicked(String highscore1){ 
    Products product = new Products(highscore1); 
    addProduct(product); 
    updateDatabase(); 
} 

//code coming from MainActivity 
public void updateDatabase(){ 
     String dbString = databaseToString(); 
     MainActivity.productText.setText(dbString); 
} 

//delete a product from the database 
public void deleteProduct(){ 
    SQLiteDatabase db = getWritableDatabase(); 
    //db.execSQL("DELETE FROM " + TABLE_PRODUCTS + " WHERE " + COLUMN_PRODUCTNAME + "=\"" + productName + "\";"); 
    db.execSQL("DELETE MIN(" + COLUMN_PRODUCTNAME + ") FROM " + TABLE_PRODUCTS +";"); 
} 


//print out the database as a string 
public String databaseToString(){ 
    String dbString = ""; 
    SQLiteDatabase db = getWritableDatabase(); 
    String query = "SELECT * FROM " + TABLE_PRODUCTS + " WHERE 1"; 


    //Cursor point to location in your results 
    Cursor c = db.query(TABLE_PRODUCTS, null, null, null, null, null, COLUMN_PRODUCTNAME +" DESC"); 
    //Cursor c = db.rawQuery(query, null); 
    //Move to the first row in your results 
    c.moveToFirst(); 

    while(!c.isAfterLast()){ 
     if(c.getString(c.getColumnIndex("productname")) != null){ 
      dbString += c.getString(c.getColumnIndex("productname")); 
      dbString += "\n"; 
     } 
     c.moveToNext(); 

    } 


    db.close(); 
    return dbString; 

}

}

调试运行

22688/com.example.emilythacker.myapplication E/SQLiteLog: (1) near "MIN": syntax error 
22688/com.example.emilythacker.myapplication E/AndroidRuntime: FATAL EXCEPTION: main 
                        Process: com.example.emilythacker.myapplication, PID: 22688 
                        android.database.sqlite.SQLiteException: near "MIN": syntax error (code 1): , while compiling: DELETE MIN(productname) FROM products; 
                        ################################################################# 
                        Error Code : 1 (SQLITE_ERROR) 
                        Caused By : SQL(query) error or missing database. 
                         (near "MIN": syntax error (code 1): , while compiling: DELETE MIN(productname) FROM products;) 
at com.example.emilythacker.myapplication.MyDBHandler.deleteProduct(MyDBHandler.java:76) 
                         at com.example.emilythacker.myapplication.MyDBHandler.addProduct(MyDBHandler.java:53) 
                         at com.example.emilythacker.myapplication.MyDBHandler.addButtonClicked(MyDBHandler.java:62) 
                         at com.example.emilythacker.myapplication.GameScreen.cancel(GameScreen.java:152) 
                         at com.example.emilythacker.myapplication.GameScreen.access$000(GameScreen.java:18) 
                         at com.example.emilythacker.myapplication.GameScreen$1.run(GameScreen.java:34

来源

2017-03-19 Ryder Thacker

尝试运行DELETE MIN（产品名称）FROM产品;手动从SQLite管理器中查看它是否正确执行。我从来没有必须删除分钟，所以不是100％确定该查询是否正确。尝试这里提到的查询http://stackoverflow.com/questions/9819168/deleting-record-with-lowest-id – altoids

异常说明了这一切：'近“MIN”：语法错误'。如果你在SQLite网站上检查[DELETE查询的语法]（https://www.sqlite.org/lang_delete.html），你可以看到你的查询是无效的（除此之外它可能在所有的SQL变种中都是无效的）。 –

并且...请避免使用'+'WHERE 1“;'这不仅**完全无用**，而且**也可能有害**。 –

logcat中的主要部分您查询的结构是错误的。试试这个：

db.execSQL("DELETE FROM products WHERE productname = (SELECT MIN(productname) FROM products)");

代替：

db.execSQL("DELETE MIN(" + COLUMN_PRODUCTNAME + ") FROM " + TABLE_PRODUCTS +";");

来源

2017-03-19 18:27:52 rafsanahmad007

无法获取SQLite的删除记录

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