将字符串拆分为数组C++

Question

如何使用getline(cin, input);分割输入字符串以输入变量？我想分裂成这样的字符数组：

char[] = { // What goes here to make it read the input variable and split it into chars } 

有没有办法做到这一点？

那你们都是新帖吗？哪一个最好？这里是凯撒密码代码我需要修改在字符数组来读取输入变量和存储它的字符：

// Test Code ONLY 
// Not A Commercial Program OR A Crypter 
// THIS IS A TEXT CIPHERER 

#include <windows.h> 
#include <cstdlib> 
#include <iostream> 
#include <string.h> 
#include <vector> 

using namespace std; 

int main() 

{ 
    string in; 
    string out; 
    char lower[25] = {a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z}; 
    char upper[25] = {A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z}; 
    char upcip[25] = {Z,Y,X,W,V,U,T,S,R,Q,P,O,N,M,L,K,J,I,H,G,F,E,D,C,B,A}; 
    char locip[25] = {z,y,x,w,v,u,t,s,r,q,p,o,n,m,l,k,j,i,h,g,f,e,d,c,b,a}; 
    cout << "Enter PlainText: "; 
    getline(cin, in); 
    // which sample goes here to read the input var char by char, then store the chars in order in a char array in your opinion? 
    return 0; 
} 

Answer 1

的字符串是已经字符数组：

for (std::string line; std::getline(std::cin, line);) 
{ 
    for (std::size_t i = 0, e = line.size(); i != e; ++i) 
    { 
     std::cout << "char[" << i << "] = '" << line[i] << "'\n"; 
    } 
} 

Answer 2

string str; 
    std::getline(cin,str); 
    char* pArr = new char[str.size() + 1]; // add 1 for zero element which is the end of string 
    strcpy(pArr,str.c_str()); 

/* 
some actions with pArr, for ex. 
while(*pArr) 
    std::cout << *pArr; // output string on the screen 

*/ 

// updated: release memory obtained from heap 
delete [] pArr;