1
我正在研究一个相当简单的promela模型。使用两个不同的模块,它充当人行横道/交通灯。第一个模块是输出当前信号的交通灯(绿色,红色,黄色,待定)。该模块还接收作为输入的称为“行人”的信号,该信号用作行人想穿过的指示器。第二个模块充当人行横道。它接收来自交通灯模块的输出信号(绿色,黄色,绿色)。它将行人信号输出到交通灯模块。这个模块简单地定义行人是否在穿越,等待或不在场。我的问题是,在Spin中运行模型时,一旦人行横道开始执行其前几个语句,它就会超时。我附加了从命令行收到的跟踪图像。我对Spin和Promela是全新的,因此我不完全确定如何使用跟踪信息来查找代码中的问题。任何帮助是极大的赞赏。为什么promela模型会超时?
下面是完整的模型代码:
mtype = {red, green, yellow, pending, none, crossing, waiting};
mtype traffic_mode;
mtype crosswalk_mode;
byte count;
chan pedestrian_chan = [0] of {byte};
chan sigR_chan = [0] of {byte};
chan sigG_chan = [0] of {byte};
chan sigY_chan = [0] of {byte};
ltl l1 {!<> (pedestrian_chan[0] == 1) && (traffic_mode == green || traffic_mode == yellow || traffic_mode == pending)}
ltl l2 {[]<> (pedestrian_chan[0] == 1) -> crosswalk_mode == crossing }
active proctype traffic_controller(chan pedestrian_in, sigR_out, sigG_out, sigY_out)
{
do
::if
::(traffic_mode == red) ->
count = count + 1;
if
::(count >= 60) ->
sigG_out ! 1;
count = 0;
traffic_mode = green;
fi
::(traffic_mode == green) ->
if
::(count < 60) ->
count = count + 1;
traffic_mode = green;
::(pedestrian_in == 1 & count < 60) ->
count = count + 1;
traffic_mode = pending;
::(pedestrian_in == 1 & count >= 60)
count = 0;
traffic_mode = yellow;
fi
::(traffic_mode == pending) ->
count = count + 1;
traffic_mode = pending;
if
::(count >= 60) ->
sigY_out ! 1;
count = 0;
traffic_mode = yellow;
fi
::(traffic_mode == yellow) ->
count = count + 1;
traffic_mode = yellow;
if
::(count >= 5) ->
sigR_out ! 1;
count = 0;
fi
fi
od
}
active proctype crosswalk(chan sigR_in, sigG_in, sigY_in, pedestrian_out)
{
do
::if
::(crosswalk_mode == crossing) ->
if
::(sigG_in == 1) -> crosswalk_mode = none;
fi
::(crosswalk_mode == none) ->
if
:: (1 == 1) -> crosswalk_mode = none;
:: (1 == 1) ->
pedestrian_out ! 1;
crosswalk_mode = waiting;
fi
::(crosswalk_mode == waiting) ->
if
::(sigR_in == 1) -> crosswalk_mode = crossing;
fi
fi
od
}
init
{
count = 0;
traffic_mode = red;
crosswalk_mode = crossing;
atomic
{
run traffic_controller(pedestrian_chan, sigR_chan, sigG_chan, sigY_chan);
run crosswalk(sigR_chan, sigG_chan, sigY_chan, pedestrian_chan);
}
}
[![enter image description here][1]][1]
感谢您的回答。这解决了超时。不过,我确实有另一个问题。一旦计数超过60,它想要做sigY_out! 1,但我收到错误“发送到未初始化的chan”。我猜这个变量连接到的通道在某种程度上是未初始化的。不完全确定如何解决这个问题。 – Flower
@花这很可能是因为你的系统中有活动的进程,输入变量初始化为0.只需删除'active'关键字即可。 –
当计数达到60时,现在它超时。 – Flower