如何在用户注册期间在Firebase中的实时数据库中存储数据？

Question

我正在制作具有用户个人资料的类似社交媒体的应用程序。我想在使用他们的uid注册时保存他们的个人资料数据。虽然注册成功，但配置文件不会保存在Firebase数据库中。我也检查了规则，并且为经过认证的用户设置了读写。

这里是我的代码：

public class RegisterActivity extends AppCompatActivity implements View.OnClickListener { 

private Button btn_reg; 
private EditText etName, etEmail, etPassword, etCPassword, etMobile, etSchoolCompany, etLocation; 
private ProgressDialog progressDialog; 
private FirebaseAuth firebaseAuth; 


@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_register); 

    Firebase.setAndroidContext(this); 

    firebaseAuth = FirebaseAuth.getInstance(); 

    progressDialog = new ProgressDialog(this); 

    btn_reg = (Button)findViewById(R.id.btnRegister); 
    etName = (EditText)findViewById(R.id.etName); 
    etEmail = (EditText)findViewById(R.id.etEmail); 
    etPassword = (EditText)findViewById(R.id.etPassword); 
    etCPassword = (EditText)findViewById(R.id.etCPassword); 
    etMobile = (EditText)findViewById(R.id.etMobile); 
    etSchoolCompany = (EditText)findViewById(R.id.etSchoolCompany); 
    etLocation = (EditText)findViewById(R.id.etLocation); 

    btn_reg.setOnClickListener(this); 
} 

@Override 
public void onClick (View view){ 
    if(view == btn_reg){ 
     registerUser(); 
    } 
} 

private void registerUser(){ 
    String name = etName.getText().toString(); 
    String mobile = etMobile.getText().toString(); 
    String SchoolCompany = etSchoolCompany.getText().toString(); 
    String location = etLocation.getText().toString(); 
    final String email = etEmail.getText().toString().trim(); 
    final String password = etPassword.getText().toString().trim(); 
    String cpassword = etCPassword.getText().toString().trim(); 

    progressDialog.setMessage("Registering.."); 
    progressDialog.show(); 

    //REGISTERING USER 
    firebaseAuth.createUserWithEmailAndPassword(email, password) 
      .addOnCompleteListener(this, new OnCompleteListener<AuthResult>() { 
       @Override 
       public void onComplete(@NonNull Task<AuthResult> task) { 
        if(task.isSuccessful()){ 

         //THIS IS FOR STORING AUTHENTICATED USER'S DATA 
         final Firebase ref = new Firebase("https://myfirebase.firebaseio.com"); 
         ref.authWithPassword(email, password, new Firebase.AuthResultHandler(){ 
          @Override 
          public void onAuthenticated(AuthData authData){ 
           // Authentication just completed successfully :) 
           Map<String, String> map = new HashMap<String, String>(); 
           map.put("provider", authData.getProvider()); 
           if(authData.getProviderData().containsKey("displayName")) { 
            map.put("displayName", authData.getProviderData().get("displayName").toString()); 
           } 
           ref.child("users").child(authData.getUid()).setValue(map); 
          } 
          @Override 
          public void onAuthenticationError(FirebaseError error) { 
       //ERRORS TODO 
          } 
         }); 
         progressDialog.hide(); 
         Toast.makeText(RegisterActivity.this, "Registered Successfully", Toast.LENGTH_SHORT).show(); 
        }else{ 
         Toast.makeText(RegisterActivity.this, "Registration failed, please try again", Toast.LENGTH_SHORT).show(); 
        } 
       } 

      }); 
} 


} 

Answer 1

从createUserWithEmailAndPassword method reference

Tries to create a new user account with the given email address and password. If successful, it also signs the user in into the app.

这意味着你不必后再次验证用户注册过程完成。

为了确保任务完成，firebaseUser不为空，最好加AuthStateListener您FirebaseAuth而不是保存数据的内部onComplete方法，该代码是在the official guide

然后你可以保存，如果该数据用户被认证。

public void onAuthStateChanged(@NonNull FirebaseAuth firebaseAuth) { 
    FirebaseUser user = firebaseAuth.getCurrentUser(); 
    if (user != null) { 
     DatabaseReference ref = FirebaseDatabase.getInstance().getReference(); 
     Map<String, String> map = new HashMap<>(); 
     map.put("provider", user.getProviders().get(0)); 
     if(user.getProviderData().containsKey("displayName")) { 
      map.put("displayName", user.getProviderData().get("displayName").toString()); 
     } 
     ref.child("users").child(user.getUid()).setValue(map); 
    } 
} 

Answer 2

假设，如果您要添加数据库的用户名，然后写

String name = etName.getText().toString().trim(); 

然后只需创建DatabaseReference类例如对象：

DatabaseReference myRootRef = FirebaseDatabase.getInstance().getReference(); 

DatabaseReference userNameRef = myRootRef.child("User Name"); 

userNameRef.setValue(name); 

// to add email 
String email = etEmail.getText().toString().trim(); 
DatabaseReference userEmail = myRootRef.child("Email "); 
userEmail.setValue(email); 

以同样的方式，你可以做它的其他东西

这将数据存储为JSON树根源在哪里是myRootRef及其子将userNameRef

Answer 3

对于其他人有类似的问题，在火力地堡没有持续性数据的常见原因是孩子的名字在Realtime Database|Rules在Java代码中不匹配的名称：

的Java代码：

再次，你应该叫：

ref.child("users").child(firebaseUser.getUid()).setValue(<YOUR_POJO_OBJECT>);

代替

ref.child("users").child(authData.getUid()).setValue(map);