从括号，括号和连字符的字符串中获取子字符串

正则表达式并不是我最强的套装，我在这种情况下遇到了一些麻烦。从括号，括号和连字符的字符串中获取子字符串

我有以下字符串：

locale (district - town) [parish]

我需要提取以下信息： 1 - 区域设置 2 - 区 3 - 镇

而且我有这些解决方案：

1 - 区域

preg_match("/([^(]*)\s/", $input_line, $output_array);

2 - 区

preg_match("/.*\(([^-]*)\s/", $input_line, $output_array);

3 - 镇

preg_match("/.*\-\s([^)]*)/", $input_line, $output_array);

而这些似乎很好地工作。但是，字符串可以呈现像任何这些：

localeA(localeB) (district - town) [parish] 
locale (district - townA(townB)) [parish] 
locale (district - townA-townB) [parish]

区域设置还可以包括其自身的括号内。城镇可以包括括号和/或自己的连字符。

这使得很难提取正确的信息。在3个场景上面，我将不得不提取：

localeA（localeB）+小区+镇

区域+小区+ townA（townB）

区域+小区+ townA-townB

我发现很难处理所有这些情况。你能帮我吗？

在此先感谢

来源

2013-08-20 user977568

[？GOT速度（http://regex101.com/r/xS9fZ1） – HamZa

@Hamza：为什么评论为什么不回答？ – anubhava

@anubhava我忙于其他事情，这是一个快速小提琴。如果我发布这个答案，我至少应该提供一些解释。 – HamZa

如果语言环境，区，镇没有空间在其中：

preg_match("/^\s*(\S+)\s*\((\S+)\s*-\s*(\S+)\)/", $input_line, $output_array);

解释：

The regular expression: 

(?-imsx:^\s*(\S+)\s*\((\S+)\s*-\s*(\S+)\)) 

matches as follows: 

NODE      EXPLANATION 
---------------------------------------------------------------------- 
(?-imsx:     group, but do not capture (case-sensitive) 
         (with^and $ matching normally) (with . not 
         matching \n) (matching whitespace and # 
         normally): 
---------------------------------------------------------------------- 
^      the beginning of the string 
---------------------------------------------------------------------- 
    \s*      whitespace (\n, \r, \t, \f, and " ") (0 or 
          more times (matching the most amount 
          possible)) 
---------------------------------------------------------------------- 
    (      group and capture to \1: 
---------------------------------------------------------------------- 
    \S+      non-whitespace (all but \n, \r, \t, \f, 
          and " ") (1 or more times (matching the 
          most amount possible)) 
---------------------------------------------------------------------- 
)      end of \1 
---------------------------------------------------------------------- 
    \s*      whitespace (\n, \r, \t, \f, and " ") (0 or 
          more times (matching the most amount 
          possible)) 
---------------------------------------------------------------------- 
    \(      '(' 
---------------------------------------------------------------------- 
    (      group and capture to \2: 
---------------------------------------------------------------------- 
    \S+      non-whitespace (all but \n, \r, \t, \f, 
          and " ") (1 or more times (matching the 
          most amount possible)) 
---------------------------------------------------------------------- 
)      end of \2 
---------------------------------------------------------------------- 
    \s*      whitespace (\n, \r, \t, \f, and " ") (0 or 
          more times (matching the most amount 
          possible)) 
---------------------------------------------------------------------- 
    -      '-' 
---------------------------------------------------------------------- 
    \s*      whitespace (\n, \r, \t, \f, and " ") (0 or 
          more times (matching the most amount 
          possible)) 
---------------------------------------------------------------------- 
    (      group and capture to \3: 
---------------------------------------------------------------------- 
    \S+      non-whitespace (all but \n, \r, \t, \f, 
          and " ") (1 or more times (matching the 
          most amount possible)) 
---------------------------------------------------------------------- 
)      end of \3 
---------------------------------------------------------------------- 
    \)      ')' 
---------------------------------------------------------------------- 
)      end of grouping 
----------------------------------------------------------------------

来源

2013-08-21 08:28:13 Toto

不知道究竟你的规则和边缘案件是，但这适用于提供的例子

preg_match('#^(.+?) \((.+?) - (.+?)\) \[(.+)\]$#',$str,$matches);

给出了这些结果（当在$str每个示例串运行）：

Array 
(
    [0] => locale (district - town) [parish] 
    [1] => locale 
    [2] => district 
    [3] => town 
    [4] => parish 
) 

Array 
(
    [0] => localeA(localeB) (district - town) [parish] 
    [1] => localeA(localeB) 
    [2] => district 
    [3] => town 
    [4] => parish 
) 

Array 
(
    [0] => locale (district - townA(townB)) [parish] 
    [1] => locale 
    [2] => district 
    [3] => townA(townB) 
    [4] => parish 
) 

Array 
(
    [0] => locale (district - townA-townB) [parish] 
    [1] => locale 
    [2] => district 
    [3] => townA-townB 
    [4] => parish 
)

来源

2013-08-21 09:15:59 SmokeyPHP

从括号，括号和连字符的字符串中获取子字符串

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