当字段唯一时选择count（）

我在vfp中使用SQL，所以我的一些命令是不同的。使用iif([condition],[if true],[if false])代替case when。当字段唯一时选择count（）

这里是我的代码：

SELECT 
    giftsource, 
    COUNT(donor) AS total_gifts, /*this is not the one that need fixed*/ 
    SUM(amt) AS total_amt, 
    SUM(iif(unique = 1 AND language != 'F' AND renew = '0' AND type = 'IN',1,0)) as d_Count_E_New_Indiv, 
    SUM(iif(unique = 1 AND language = 'F' AND renew = '0' AND type = 'IN',1,0)) as d_Count_F_New_Indiv, 
    SUM(iif(unique = 1 AND language != 'F' AND renew != '0' AND type = 'IN',1,0)) as d_Count_E_Re_Indiv, 
    SUM(iif(unique = 1 AND language = 'F' AND renew != '0' AND type = 'IN',1,0)) as d_Count_F_Re_Indiv, 
    SUM(iif(unique = 1 AND language != 'F' AND renew = '0' AND type != 'IN',1,0)) as d_Count_E_New_Org, 
    SUM(iif(unique = 1 AND language = 'F' AND renew = '0' AND type != 'IN',1,0)) as d_Count_F_New_Org, 
    SUM(iif(unique = 1 AND language != 'F' AND renew != '0' AND type != 'IN',1,0)) as d_Count_E_Re_Org, 
    SUM(iif(unique = 1 AND language = 'F' AND renew != '0' AND type != 'IN',1,0)) as d_Count_F_Re_Org, 
FROM (select *, 
      cast(/* equivalent to a bunch of if elses*/ 
       iif( list_code="WEB","1", 
       iif( list_code="GRO","2", 
       iif( list_code="CHO","3", 
       iif( list_code="TEL","4", 
       iif( list_code="TES","5", 
       iif( list_code="POS" AND amt < 10000,"6", 
       iif((LIKE(list_code,"4%") OR list_code = "4") AND amt < 10000,"7", 
       iif((LIKE(list_code,"4%") OR list_code = "4" OR list_code = "POS") AND amt >= 10000,"8", 
       iif( LIKE(list_code,"9%") OR list_code = "9","9", 
       "10"))))))))) as c(1)) 
      as giftsource 
     from cGift) gift 
    LEFT JOIN 
      (select didnumb, language, type from dp) d 
     on cast(gift.donor as i) = cast(d.didnumb as i) 
    LEFT JOIN /*this does not do what i want it to*/ 
      (select min(gidnumb) gid, 1 as unique from cGift group by donor) uGift 
     on gift.gidnumb = uGift.gid 
GROUP BY giftsource 
ORDER BY giftsource

这段代码应该做的是找到每个礼品类内捐了许多捐助者。它不应该统计同一领域内的重复捐赠者（即相同的list_code/lang/renew /等），但如果是另一个领域，它应该计数捐献者两次。

示例：捐献者＃3只能在d_Count_E_New_Indiv中计数一次，但也可以在d_Count_E_New_Org中计数。

gidnumb是此表中的主键。

随着我的第二次加入，我给表中的第一个捐助者附加了一个字段（名为unique）。这是行不通的，因为它只计算一个领域的捐助者。

有人能告诉我什么是正确的做法吗？我还有更多的SUM（...）不是基于独特的捐助者，所以我宁愿不要屠杀我的选择太多。

编辑：我固定它通过以下select count(distinct IIF(renew = '0' AND lang != 'F',donor,0)) FROM dpgift

来源

2012-02-27 slicedtoad

如何使用单个查询所有相关领域组（貌似giftsource，语言，更新和类型），以获得一个记录你所需要的次数来对每个组合：

SELECT giftsource, language, renew, type, COUNT(*) ; 
    FROM <whatever tables and joins you need> ; 
    GROUP BY giftsource, language, renew, type

然后，你可以将它加入到任何你需要的地方，或者使用一些Xbase代码将它拉入单行。您也可以查看交叉表（使用VFPXTab或第三方工具之一）来转发数据。

来源

2012-02-27 22:28:54

谢谢，我已经实现了与此非常相似的内容。 – slicedtoad 2012-02-28 15:25:00

我想你可以逃脱COUNT（不同的供体）AS total_gifts，我没有视觉狐狸亲和做了一些谷歌上搜索，它被提及。

来源

2012-02-27 17:33:03

是的，我可以做'选择计数（不同的捐助者）'。我怎么会把这个到我的代码，但？我使用'sum（iif（expression，1,0））'因为我需要一个过滤器。 – slicedtoad 2012-02-27 18:24:51

哦，这不是需要修复的total_gifts。这是所有的总和（）作为计数。 – slicedtoad 2012-02-27 18:28:07

当字段唯一时选择count（）

回答

相关问题