0
@Entity
public class Dept {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;
@OneToMany(
mappedBy = "dept",
cascade = CascadeType.ALL
)
private List<Employee> employees = new ArrayList<Employee>();
public void addEmployee(Employee emp) {
this.employees.add(emp);
}
}
@Entity
public class Employee {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;
@Column private Integer age;
public Employee(Integer a) {
this.age = a;
}
}
然后在单元测试我这样做(OpenJPA的使用):
// ...
Dept dept = new Dept();
dept.addEmployee(new Employee(25));
this.em.persist(dept);
OpenJPA的说:
Caused by: <openjpa-1.2.1-r752877:753278 nonfatal general error>
org.apache.openjpa.persistence.PersistenceException: Attempt to insert
null into a non-nullable column: column: ID table: EMPLOYEE in
statement [INSERT INTO employee (age) VALUES (?)]
{prepstmnt 841687127 INSERT INTO employee (age) VALUES (?)
[params=(int) 25]} [code=-10, state=23000]
为什么ID是不自动生成?
你或许应该检查你的代码: @Column私人整数年龄; 公共雇员(整数年龄){ this.age =年龄; } – Pau 2010-11-17 13:06:49
您是否有员工方的部门属性?这似乎在代码中缺失。借助该映射,侧面是拥有实体。尝试删除mappedby,而不是做坚持。 – lalit 2010-11-17 13:31:48