显示带有HTTP请求的网页

Question

我正在搜索一些关于发送HTTP请求的示例，以便通过使用java在浏览器上显示网页。我找不到一个简单的例子。你有什么建议吗 ？我应该在哪里寻找一个有解释的好例子？谢谢

Answer 1

使用

Desktop.browse("http://stackoverflow.com/questions/12844363/displaying-a-web-page-with-http-request"); 

---

此外

• API Doc

Answer 2

请参见您可以在第j使用 java.net.URL, java.net.URLConnection, java.io.InputStream, org.apache.commons.io.IOUtils管理HTTP请求AVA应用

下面是一个例子类 -

public class HttpUtil 
{ 
    static URL url; 
    static URLConnection urlConn; 
    static DataOutputStream out; 
    static BufferedReader input; 

    static public String get(String _url) 
    { 
     try 
     { 
      url = new URL(_url.replace(" ", "%20")); 

      InputStream input = url.openStream(); 
      StringWriter writer = new StringWriter(); 
      IOUtils.copy(input, writer); 
      return writer.toString(); 

     } 
     catch (Exception e) 
     { 
      return "ERROR: " + e.getMessage(); 
     } 
    } 

    static public String post(String _url, String postData) 
    { 
     String result = ""; 

     try 
     { 
      url = new URL(_url); 

      urlConn = url.openConnection(); 
      urlConn.setDoInput(true); 
      urlConn.setDoOutput(true); 
      urlConn.setUseCaches(false); 
      urlConn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); 

      out = new DataOutputStream(urlConn.getOutputStream()); 
      String content = postData; 

      out.writeBytes(content); // send the data 

      out.flush(); 
      out.close(); 

      DataInputStream in = new DataInputStream(urlConn.getInputStream()); 
      input = new BufferedReader(new InputStreamReader(in)); 

      String str; 

      while ((str = input.readLine()) != null) 
      { 
       result = result + str + "\n"; 
      } 

      input.close(); 
     } 
     catch (Exception e) 
     { 
      System.err.println(e.toString()); 
      return null; 
     } 

     return result; 
    } 
} 

您也可以使用这个小片段火了在Java Web浏览器 -

URI url = new URI("file:/" + ur); // or an absolute path to a website http://google.com/ 

Desktop.getDesktop().browse(url);