显示从数据库填充的下拉列表值（SQL Server）

Question

我正在尝试显示从数据库填充的动态下拉列表的已保存值。我的代码如下：

<?PHP 
$server = "xxx"; 
$options = array( "UID" => "xxx", "PWD" => "xxx", "Database" => "xxx"); 
$conn = sqlsrv_connect($server, $options); 
if ($conn === false) die("<pre>".print_r(sqlsrv_errors(), true)); 
echo " "; 

$myquery="SELECT Department FROM Change_Details WHERE id='2137'"; 
$fetched=sqlsrv_query($conn,$myquery) ; 
if($fetched === false) { die(print_r(sqlsrv_errors(), true));} 
    while($res=sqlsrv_fetch_array($fetched,SQLSRV_FETCH_ASSOC)) 
    { 
     $Department=$res['Department']; 
    } 
?> 

<div class="container"> <!-- Department --> 
    <div class="form-inline clearfix"> 
     <label class="col-md-5">Department initiating the Request</label> 
      <label name="Department"></label> 
       <div class="col-md-5"> 
          <?PHP 
          echo "<select name= 'Department' class='form-control selectpicker' onChange='getState(this.value)' Required>"; 
          echo '<option value="$Department">'.'--Please Select Department--'.'</option>'; 
          $sql = "SELECT ID,Name FROM Departments"; 
          $query = sqlsrv_query($conn,$sql); 
          $query_display = sqlsrv_query($conn,$sql); 
          while($row=sqlsrv_fetch_array($query_display,SQLSRV_FETCH_ASSOC)){ 
          echo "<option value='". $row['Name']."'>".$row['Name']. '</option>'; 
          } 
          echo "</select>"; 
         ?> 
       </div> 
    </div> 
</div><br/> 

什么是工作：下拉列表正在填充完美，该值也保存到数据库中。

我需要：想要显示从数据库和下拉列表中保存的值以及用户再次编辑该字段。感谢所有帮助:)

Answer 1

遍历结果集，你可以做这样的事情时，你需要获得当前用户选择的值，则：

while($row=sqlsrv_fetch_array($query_display,SQLSRV_FETCH_ASSOC)){ 
    if ($Department == $row['Name']) { 
     echo "<option selected='selected' value='". $row['Name']."'>".$row['Name']. '</option>'; 
     continue; 
    } 

    echo "<option value='". $row['Name']."'>".$row['Name']. '</option>'; 
}