PHP：如何从不同的数组中获取公共值？

Question

我有两个数组如下： -

$a = ["2","11","6"]; 
$b = ["6","7"]; 
$c = array_diff($a, $b); 

$c = ["2","11"]; 

结果在$c是错误的。我想要的结果应该是$c = [6]

换句话说我想在这两个数组中的通用元素被返回！但它给错误的错误。请帮助我？

Answer 1

使用array_intersect()

$a = ["2","11","6"]; 
$b = ["6","7"]; 
$c = array_intersect($a, $b); 

演示：https://eval.in/682653

Answer 2

您可以使用array_intersect

$c = array_intersect($a, $b); 

Answer 3

$a = ["2","11","6"]; 
$b = ["6","7"]; 
$c = array_intersect($a,$b); 

Answer 4

使用array_intersect（http://php.net/manual/en/function.array-intersect.php）

<?php 
$a = ["2","11","6"]; 
$b = ["6","7"]; 
$c = array_intersect($a, $b); 

print_r($c) 

?>