PDOException错误 - Drupal的7

Question

当我创建了一个形象的内容类型和添加内容，出现此错误：

DOException: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'base.12' in 'where clause': SELECT base.tid AS tid, base.vid AS vid, base.name AS name, base.description AS description, base.format AS format, base.weight AS weight, v.machine_name AS vocabulary_machine_name FROM {taxonomy_term_data} base INNER JOIN {taxonomy_vocabulary} v ON base.vid = v.vid WHERE (base.12 = :db_condition_placeholder_0) ; Array ([:db_condition_placeholder_0] => 12) in DrupalDefaultEntityController->load() (line 196 of /Users/httdocs/includes/entity.inc). 

但我不使用分类术语，词汇等...我怎么能修理它？

Answer 1

PGSQL查询，如： -

SELECT base.tid AS tid, base.vid AS vid, base.name AS name, base.description AS description, base.format AS format, base.weight AS weight, v.machine_name AS vocabulary_machine_name FROM taxonomy_term_data.base INNER JOIN taxonomy_vocabulary.v ON base.vid = v.vid WHERE (base.name = v.machine_name) ; 

在你查询你通过base.12，那里与12名没有列，因此它显示的错误