从我能收集的信息来看,这应该起作用,不是吗?初始化基类
struct ViewOfFile {
void* p = nullptr;
ViewOfFile(HANDLE hMap, int64_t OffsetB, SIZE_T SizeB, bool WriteAccess) {
DWORD ViewAccessMode = FILE_MAP_READ | (WriteAccess ? FILE_MAP_WRITE : NULL);
LARGE_INTEGER LI = { OffsetB };
p = MapViewOfFile(hMap, ViewAccessMode, LI.HighPart, LI.LowPart, SizeB);
if (p == nullptr) throw Exception("ViewOfFile: Failed to create view.");
}
~ViewOfFile() {
if (p) UnmapViewOfFile(p);
}
operator void*() const { return p; }
operator char*() const { return reinterpret_cast<char*>(p); }
};
template <typename T>
struct ViewOfFileAs : ViewOfFile {
T* as;
ViewOfFile(HANDLE hMap, int64_t OffsetB, SIZE_T SizeB, bool WriteAccess) : ViewOfFile(hMap, OffsetB, SizeB, WriteAccess) {
as = reinterpret_cast<T*>(p);
}
};
但是,模板类的构造函数给我一个错误“只有构造函数可以有基/成员初始化列表”。这是为什么发生?
无关,但你为什么用'NULL'宏来写一个整数值? –
您可能想要将模板构造函数从ViewOfFile重命名为ViewOfFileAs –
@NeilKirk,因为它应该是0并且像其他宏一样是紫色的,它的时尚选择 – user81993