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我想一些JSON数据trnsform到一个PHP数组,这是我的代码:得到JSON文件(卷曲)数据
<?php
$obj1=json_decode('http://ddragon.leagueoflegends.com/cdn/3.15.5/data/en_US/champion/Aatrox.json', true);
$championname = $obj1[data][aatrox][name];
echo $championname;
?>
的问题是,我不知道怎么弄的来自http://ddragon.leagueoflegends.com/cdn/3.15.5/data/en_US/champion/Aatrox.json的数据
我该如何使此代码有效?
那的确没有工作,现在我想$ OBJ1 [ '数据'] [ 'aatrox'] [ '名'];是错误的,因为它不给我变量。这是从http://ddragon.leagueoflegends.com/cdn/3.15.5/data/en_US/champion/Aatrox.json 阵列 ( [型] =>冠军 [格式] => standAloneComplex 阵列[版] => 3.15.5 [数据] =>数组 ( [Aatrox] =>数组 ( [ID] => Aatrox [键] => 266 [名称] => Aatrox [标题] => Darkin Blade – user3104376
它与这样的大写'A':'$ obj1 ['data'] ['Aatrox'] ['name']' –