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我在我的程序中使用ajax调用。我得到这样的错误:__init __()得到了一个意想不到的关键字参数'password'django
TypeError: __init__() got an unexpected keyword argument 'password'
我在模型如下:
class Student(models.Model):
name = models.CharField(max_length = 20)
password = models.CharField(max_length = 100)
email = models.CharField(max_length = 10)
class StudentForm(forms.ModelForm):
class Meta:
model = Student
fields = '__all__
现在,下面是我的模板:
`<form id = "post_submit" action="{% url "apply" %}" method="POST">
{% csrf_token %}
{% for field in form %}
<p>{{field.label}} : {{field}}</p>
{% endfor %}
<p><input type="submit" name="Submit"></p>
</form>
<p id="click_option">Click here.</p>
Ajax调用使用由:
$.ajax({
// using this for csrf handling
// alert(" i am in ajax");
// console.log(" iam ");
url : "/apply/",
type : "POST",
data :
{
csrfmiddlewaretoken:document.getElementsByName('csrfmiddlewaretoken')[0].value,
name : $('#id_name').val(),
email : $('#id_email').val(),
password : $('#id_password').val(),
},
success: function(json) {
alert("Congratulations! You scored: " + json['status']);
},
// error
})
});
在后端的视图是:
高清应用(要求):
if request.method == 'POST':
name = request.POST.get('name')
email = request.POST.get('email')
password = request.POST.get('password')
student = StudentForm(name = name, email = email, password = password)
student.save()
data = {"status" : "success"}
return JsonResponse(data)
else:
data = {"status" : "failure"}
return JsonResponse(data)
您正在调用未定义的StudentForm构造函数。正确的方法可以是创建对象,然后分配值 – Freddy
好吧,我得到了问题。但为什么只有'password'的类型错误?为什么不为所有的价值? – learner
“TypeError”一次只显示一个字段名称。如果将其更改为'student = StudentForm(name = name,email = email)',那么对于其他字段中的其中一个,您将得到相同的错误。 – Alasdair