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我写了下面的SQL语句,在测试表,我有4个记录,并对coa_body表我也有四个记录,这个查询:MySQL来返回独特的记录
SELECT `name`, `compedia`, `specification`
FROM (`tests` t, `coa_body` cb)
JOIN
`request_details` rd
ON `t`.`id` = `rd`.`test_id`
WHERE `rd`.`request_id` = 'NDQA201303001' AND cb.labref = 'NDQA201303001';
回报:
1.name compedia说明书
Assay Alphy poxy
pH(Acidity/Alkalinity) Alphy poxy
Sterility Alphy poxy
Bacterial Endotoxin Test Alphy poxy
Assay poxy alphy
pH(Acidity/Alkalinity) poxy alphy
Sterility poxy alphy
Bacterial Endotoxin Test poxy alphy
Assay alphy1 poxy1
pH(Acidity/Alkalinity) alphy1 poxy1
Sterility alphy1 poxy1
Bacterial Endotoxin Test alphy1 poxy1
Assay poxy1 alphy1
pH(Acidity/Alkalinity) poxy1 alphy1
Sterility poxy1 alphy1
Bacterial Endotoxin Test poxy1 alphy1
2.coa_body表如下: ID labref compedia规范
1 NDQA201303001 Alphy poxy
2 NDQA201303001 poxy alphy
3 NDQA201303001 alphy1 poxy1
4 NDQA201303001 poxy1 alphy1
3.我只需要4条一模一样这样
name compedia specification
Assay Alphy poxy
pH(Acidity/Alkalinity) poxy alphy
Sterility alphy1 poxy1
Bacterial Endotoxin Test poxy1 alphy1
4.at查询结束的coa_body表,如果我添加GROUP BY t.name语句,它返回
name compedia specification
Assay Alphy poxy
Bacterial Endotoxin Test Alphy poxy
pH(Acidity/Alkalinity) Alphy poxy
Sterility Alphy poxy
这是不是想让我想要的,我想要的结果是一个在3号
请不要使用不适用于您的问题的标签 –
好的,下次再记住这一点 – alphy