阵列格式错误

-3

{ “contractID”：27112016185818 “contractName”： “DDF”， “供应商ID”：5 “supplierName”： “HH”， “的productID”：44 ， “产品名称”： “GG”， “计量单位”： “UU”， “数量”：6， “pricePerUOM”：6， “totalPrice”：36， “货币”： “INR”， “supplyByDate”： “01112016” “createdDate”： “27112016”， “loginuser”： “买方”， “chain_id”： “supplychainintegrity”， “高度”：244432 “num_txs”：1， “pendingWith”： “”， “block_hash”：“哈希”， “block_data”： “数据”， “data_hash”： “datahash”， “block_time”： “时间”}

我想把它转换成以下

[{"contractID":27112016185818,"contractName":"ddf","supplierID":5,"supplierName":"hh","productID":44,"productName":"gg","uom":"uu","quantity":6,"pricePerUOM":6,"totalPrice":36,"currency":"inr","supplyByDate":"01112016","createdDate":"27112016","loginuser":"buyer","chain_id":"supplychainintegrity","height":244432,"num_txs":1,"pendingWith":"","block_hash":"hash","block_data":"data","data_hash":"datahash","block_time":"time"}]

它为json stringification。

jsonObj["row"]=currentArray; 
newArray=JSON.stringify(jsonObj);

我newArray如下

{"row":{"contractID":27112016185818,"contractName":"ddf","supplierID":5,"supplierName":"hh","productID":44,"productName":"gg","uom":"uu","quantity":6,"pricePerUOM":6,"totalPrice":36,"currency":"inr","supplyByDate":"01112016","createdDate":"27112016","loginuser":"buyer","chain_id":"supplychainintegrity","height":244432,"num_txs":1,"pendingWith":"","block_hash":"hash","block_data":"data","data_hash":"datahash","block_time":"time"}}

需要如下

{ “行”：[{ “contractID”：27112016185818， “contractName”： “DDF”， “供应商ID”： 5， “supplierName”： “HH”， “的productID”：44， “产品名称”： “GG”， “计量单位”： “UU”， “数量”：6， “pricePerUOM”：6， “totalPrice”：36， “货币”： “INR”， “supplyByDate”： “01112016”， “createdDate”： “27112016”， “loginuser”： “买方”， “chain_id”： “supplychainintegrity”， “高度”：244432， “num_txs”： 1， “pendingWith”： “”， “block_hash”： “散列”， “block_data”： “数据”， “data_hash”：” datahash”， “block_time”： “时间”}]}

来源

2016-11-27 Adarsh M Pallickal

，这样的差异是清晰的，请格式化你的JSON。 –

@Tim Biegeleisen我没有得到你 –

试试[this]（http://jsonlint.com/）网站。这是一个强大的工具，用于确定您的JSON是否结构合理，如果不正确，它会告诉您哪里存在不一致。 – FDavidov

你可以简单的做到这一点，

$scope.newarray = []; 
$scope.myObj = data.row; 
$scope.newarray.push($scope.myObj); 
console.log($scope.newarray);

DEMO

来源

2016-11-27 13:48:42 Sajeetharan

阵列格式错误

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