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我正在学习android和我的代码工作正常。它从网站提取数据并将其显示在列表中。但是当subcat==1它有9个项目要获取。它显示7个不同的项目并重复两个项目。首先它只显示了四个是NullPointerException第五个图像没有名称，所以它重复4次图像直到9次，但现在一切都很好，但它仍然只显示7，然后重复2次。这里是我的代码：listview在customadapter中重复项目
public class JSONAsyncTask extends AsyncTask<String, Void, Void> {
ProgressDialog pd;
Context context;
JSONAsyncTask(Context context) {
this.context = context;
}
@Override
protected void onPreExecute() {
super.onPreExecute();
pd = new ProgressDialog(context);
pd.setIndeterminate(true);
pd.setCancelable(false);
pd.setCanceledOnTouchOutside(false);
pd.setMessage("Please wait..\nLoading data");
pd.show();
}
@Override
protected Void doInBackground(String... strings) {
ArrayList<item> jsonArrayList = new ArrayList<item>();
try {
HttpClient client = new DefaultHttpClient();
HttpGet httpget = new HttpGet("http://avdeal.in/get_all_products.php");
HttpResponse response = client.execute(httpget);
HttpEntity entity = response.getEntity();
String data = EntityUtils.toString(entity);
JSONObject jsonObject = new JSONObject(data);
if (jsonObject != null) {
String posts = jsonObject.getString("products");
JSONArray postsArray = new JSONArray(posts);
if (postsArray != null) {
if (postsArray.length() > 0) {
for (int i = 0; i < postsArray.length(); i++) {
JSONObject postsObject = postsArray
.getJSONObject(i);
int subcat = postsObject.getInt("subcat_id");
if (subcats == subcat) {
int id=postsObject.getInt("id");
String title = postsObject.getString("product_title");
String price = postsObject.getString("product_price");
String url = "http://avdeal.in/seller/upload_images/" + postsObject.getString("product_url");
list1.add(new item(id, title, price, url));
}
}
}
}
}
} catch (Exception e) {
e.printStackTrace();
return null;
}
return null;
}
@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
if (list1 != null) {
pd.dismiss();
adp = new actorAdapter(context, R.layout.listview, list1);
lv.setAdapter(adp);
adp.notifyDataSetChanged();
}
else {
pd.setMessage("No internet access");
}
lv.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) {
Toast.makeText(itemView.this, "Please Wait " + i + 1, Toast.LENGTH_SHORT).show();
int id1 = list1.get(i).getId();
String name = list1.get(i).getName();
String price = list1.get(i).getPrice();
Bitmap bitmap = list1.get(i).getImage();
if (bitmap == null) {
Intent intent = new Intent(context, productDetail.class);
intent.putExtra("name", name);
intent.putExtra("price", price);
intent.putExtra("id", id1);
intent.putExtra("imagena", 1);
startActivity(intent);
} else {
ByteArrayOutputStream stream = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.PNG, 100, stream);
byte[] byteArray = stream.toByteArray();
Intent intent = new Intent(context, productDetail.class);
intent.putExtra("name", name);
intent.putExtra("price", price);
intent.putExtra("image", byteArray);
intent.putExtra("id", id1);
startActivity(intent);
}
}
});
}
}
private class ImageLoadTask extends AsyncTask<String, String, Bitmap>{
Context context;
ImageLoadTask(Context context) {
this.context = context;
}
@Override
protected Bitmap doInBackground(String... strings) {
for(int i = 0 ; i < list1.size() ; i++)
{
if (list1.get(i).getImage()==null);
{
String url=list1.get(i).getUrl();
InputStream is = null;
try {
is = (InputStream) new URL(url).getContent();
} catch (IOException e) {
e.printStackTrace();
}
Bitmap b = BitmapFactory.decodeStream(is);
list1.set(i, new item(list1.get(i).getId(), list1.get(i).getName(), list1.get(i).getPrice(), list1.get(i).getUrl() ,b));
}
}
return null;
}
@Override
protected void onProgressUpdate(String... values) {
super.onProgressUpdate(values);
}
protected void onPostExecute(Bitmap result){
super.onPostExecute(result);
adp = new actorAdapter(context, R.layout.listview, list1);
lv.setAdapter(adp);
adp.notifyDataSetChanged();
}
}
我可以做任何事情来延迟加载图像吗？我试图创建另一个AsyncTask，但它显示所有图像加载时的图像。
只要下载一张图像，我可以更新我的ListView吗？
请帮忙。无法自己弄清楚。这两个问题阻止我学习更多。
3210
重复列表？ – Shashank
您的AsyncTask代码看起来不错，发布您的适配器代码... – Rami
是啊，现在工作。你可以告诉我如何为每个图像调用异步。当我从主线程调用它时。它强制停止，我试图保持主线程中的第一个异步并调用另一个中的每个图像异步它不加载任何东西，并捕获异常。告诉我如何实现，而不使用第三方库 – Shashank