我跟随了UA教程并获得了我的APID,并成功地在我的Android设备上收到了测试推送消息。城市飞艇推码
现在我想要做的下一件事就是使用JAVA定位我的设备并发送推送消息。 从我目前看到的最好的方式来实现这一点是使用他们的Web API。
但是当我试图发送一个消息后,我总是得到以下错误:
产生java.io.IOException:服务器返回的HTTP响应代码:401网址:https://go.urbanairship.com/api/push/ 在sun.net .www.protocol.http.HttpURLConnection.getInputStream(Unknown Source) at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(Unknown Source) at com.Sender.Sender.main(Sender.java:56)
这是我使用的代码:
package com.Sender;
import java.io.BufferedReader;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.net.Authenticator;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLConnection;
public class Sender {
/**
* @param args
*/
public static void main(String[] args) {
try {
String responseString = "";
String outputString = "";
String username = "MWMoRVhmRXOG6IrvhMm-BA";
String password = "ebsJS2iXR5aMJcOKe4rCcA";
MyAuthenticator ma= new MyAuthenticator(username, password);
Authenticator.setDefault(ma);
URL url = new URL("https://go.urbanairship.com/api/push/");
URLConnection urlConnection = url.openConnection();
HttpURLConnection httpConn = (HttpURLConnection) urlConnection;
ByteArrayOutputStream bout = new ByteArrayOutputStream();
String APID = "23eef280-19c8-40fc-b798-788f50e255a2";
String postdata = "{\"android\": {\"alert\": \"Hello from JAVA!\"}, \"apids\": [\""+APID+"\"]}";
byte[] buffer = new byte[postdata.length()];
buffer = postdata.getBytes("UTF8");
bout.write(buffer);
byte[] b = bout.toByteArray();
httpConn.setRequestProperty("Content-Length",
String.valueOf(b.length));
httpConn.setRequestProperty("Content-Type", "application/json");
httpConn.setRequestMethod("POST");
httpConn.setDoOutput(true);
httpConn.setDoInput(true);
OutputStream out = httpConn.getOutputStream();
out.write(b);
out.close();
InputStreamReader isr = new InputStreamReader(
httpConn.getInputStream());
BufferedReader in = new BufferedReader(isr);
while ((responseString = in.readLine()) != null) {
outputString = outputString + responseString;
}
System.out.println(outputString);
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e1) {
e1.printStackTrace();
}
}
}
你能帮助我吗?
谢谢你的回复。但是“Authenticator.setDefault(ma)”这行代码如何呢? 。我认为这需要处理所有事情。否则,我应该如何将Authenticator作为标题的一部分? – Ivelius 2012-01-29 13:17:46
我不认为setDefaul就够了。在我的回答中发布的链接中有如何将Authenticator设置为标题的一部分。 – kosa 2012-01-29 15:54:16
好吧,我按照指南,现在我得到400错误。这是我的新代码和错误说明,下面http://pastie.org/3281240 – Ivelius 2012-01-30 09:47:23