Python电话号码程序

我需要编写一个程序，将打印到屏幕上的所有可能通过具有前缀555的800电话号码生成的单词（以及相关号码）。请记住，数字1和0在键盘上没有与它们相关的字母。Python电话号码程序

我试图到目前为止如下：

alph_num_dict = {'a': '2', 'b': '2', 'c': '2', 
      'd': '3', 'e': '3', 'f': '3', 
      'g': '4', 'h': '4', 'i': '4', 
      'j': '5', 'k': '5', 'l': '5', 
      'm': '6', 'n': '6', 'o': '6', 
      'p': '7', 'q': '7', 'r': '7', 's': '7', 
      't': '8', 'u': '8', 'v': '8', 
      'w': '9', 'x': '9', 'y': '9', 'z': '9'} 

for letter, digit in alph_num_dict.items(): 
    print ("1.800.555." + str(digit) + str(digit) + str(digit) + str(digit), end=" ") 
    print (" 1.800.555." + str(letter) + str(letter) + str(letter) + str(letter))

，我得到的输出是：

1.800.555.2222  1.800.555.aaaa 
1.800.555.2222  1.800.555.bbbb 
1.800.555.2222  1.800.555.cccc 
1.800.555.3333  1.800.555.dddd 
1.800.555.3333  1.800.555.eeee 
1.800.555.3333  1.800.555.ffff 
1.800.555.4444  1.800.555.gggg 
1.800.555.4444  1.800.555.hhhh 
1.800.555.4444  1.800.555.iiii 
1.800.555.5555  1.800.555.jjjj 
1.800.555.5555  1.800.555.kkkk 
1.800.555.5555  1.800.555.llll 
1.800.555.6666  1.800.555.mmmm 
1.800.555.6666  1.800.555.nnnn 
1.800.555.6666  1.800.555.oooo 
1.800.555.7777  1.800.555.pppp 
1.800.555.7777  1.800.555.qqqq 
1.800.555.7777  1.800.555.rrrr 
1.800.555.7777  1.800.555.ssss 
1.800.555.8888  1.800.555.tttt 
1.800.555.8888  1.800.555.uuuu 
1.800.555.8888  1.800.555.vvvv 
1.800.555.9999  1.800.555.wwww 
1.800.555.9999  1.800.555.xxxx 
1.800.555.9999  1.800.555.yyyy 
1.800.555.9999  1.800.555.zzzz

这是唯一我需要输出的一部分。我需要能够输出所有其他可能的组合（其中有456,976个）。我无法弄清楚如何获得所有可能组合的输出。

要明确的事情了，我需要的输出开始寻找类似：

1.800.555.2222  1.800.555.aaaa 
1.800.555.2222  1.800.555.aaab 
1.800.555.2222  1.800.555.aaac 
1.800.555.2223  1.800.555.aaad 
1.800.555.2223  1.800.555.aaae 
1.800.555.2223  1.800.555.aaaf

任何帮助，这将不胜感激。

来源

2017-03-07 Sheriff44

http://stackoverflow.com/questions/464864/how-to-get-all-possible-combinations-of-a-list-s-elements –

你可能想看看排列函数。

alph_num_dict = {'a': '2', 'b': '2', 'c': '2', 
      'd': '3', 'e': '3', 'f': '3', 
      'g': '4', 'h': '4', 'i': '4', 
      'j': '5', 'k': '5', 'l': '5', 
      'm': '6', 'n': '6', 'o': '6', 
      'p': '7', 'q': '7', 'r': '7', 's': '7', 
      't': '8', 'u': '8', 'v': '8', 
      'w': '9', 'x': '9', 'y': '9', 'z': '9'} 

from itertools import permutations 

all_numbers = permutations(alph_num_dict, 4): 
for number in all_numbers: 
    # TODO: Iterate through all_numbers and do translation

来源

2017-03-07 03:51:56 SuperTetelman

Python电话号码程序

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