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将我的NSString处理成有效的JSON字符串时遇到一些麻烦。正确格式化NSString for JSON
NSString *version = @"1.1";
NSString *callMethod = @"auth.login";
NSString *paramsConfig = [NSString stringWithFormat:@"{\"email\":\"%@\",\"password\":\"%@\"}", usernameString, passwordString];
int queryId = arc4random()% 10000000;
NSDictionary *userData = [NSDictionary dictionaryWithObjectsAndKeys:version, @"version", callMethod, @"method", [NSNumber numberWithInt:queryId], @"id", paramsConfig, @"params", nil];
NSString* jsonString = [userData JSONRepresentation];
预期JSON字符串:
{"version":"1.1","params":"{"email":"s","password":"s"}","id":12345678,"method":"auth.login"}
实际JSON字符串:
{"version":"1.1","params":"{\"email\":\"s\",\"password\":\"s\"}","id":12345678,"method":"auth.login"}
不能确定我要去哪里错了。有什么想法吗?
感谢
山姆
现货! 非常感谢你的魅力。 – Sam 2010-05-14 13:24:22