所有的行至少有一个孩子都有自己的孩子通过一个条件

Question

我对SQL查询有点麻烦，并且认为我会征求人群的智慧来查看我错过的东西。我很确定下面的工作，但它似乎很差，我想知道是否有一个更聪明的方法（理想情况下使用连接而不是子选择）来做到这一点。

的问题

比方说，我有一些表：

Prize 
    - PrizeId 

RulePrize_Map 
    - PrizeId 
    - RuleId 

Rule 
    - RuleId 

Conditional 
    - ConditionalId 
    - RuleId 
    - InputId 
    - ExpectedValue (bit) 

Input 
    - InputId 

一个Prize当至少一个Rule为真赢了。 A Rule当全部的Conditionals为真时为真。当InputId存在或不存在于Input表中时，Conditional为“真”，如ExpectedValue指定的字段。这也许可以等同于：Count(InputId in Input table) = ExpectedValue对于Conditional'sInputId。

一些例子：

Conditional (InputId = 11, ExpectedValue = 1) -> True if InputId 11 in Input Table 
Conditional (InputId = 12, ExpectedValue = 0) -> True if Inputid 12 NOT in Input Table 

我的目标

我想所有Prizes其中至少一个Rule是 “真”。我会解决：“所有Rules这是真的”。

我尝试

select p.PrizeId from Prize p INNER JOIN RulePrize_Map rpm ON rpm.PrizeId = p.PrizeId 
WHERE p.PrizeId IN 
(select r.PrizeId from Rule r 
where 
    (select count(*) from Conditional c1 where c1.RuleId = r.RuleId) 
    = 
    (select count(*) from Conditional c2 
    where c2.RuleId = r.RuleId AND 
    (select count(*) from Input i where i.InputId = c2.InputId) = c2.ExpectedValue 
) 
) 
GROUP BY p.prizeId 

Answer 1

的问题改了一下，所以我重做的答案...

SELECT 
    PrizeId 
FROM 
    (
    SELECT 
    PrizeRule_Map.PrizeId, 
    PrizeRule_Map.RuleId 
    FROM 
    PrizeRule_Map 
    INNER JOIN 
    Rule 
     ON Rule.RuleId = PrizeRule_Map.RuleId 
    INNER JOIN 
    Conditional 
     ON Conditional.RuleId = Rule.RuleID 
    LEFT JOIN 
    Input 
     ON Input.InputId = Conditional.InputID 
    GROUP BY 
    PrizeRule_Map.PrizeId, 
    PrizeRule_Map.RuleId 
    HAVING 
    COUNT(*) = SUM(CASE Conditional.ExpectedValue 
        WHEN 1 THEN CASE WHEN Input.InputId IS NULL THEN 0 ELSE 1 END 
        WHEN 0 THEN CASE WHEN Input.InputId IS NULL THEN 1 ELSE 0 END 
        END 
        ) 
) 
    AS map 
GROUP BY 
    PrizeId 

Answer 2

尝试以下操作：

SELECT Rule.RuleId, Rule.RuleName 
FROM Rule 
INNER JOIN Conditional ON Rule.RuleId = Conditional.RuleId 
Where Conditional.ExpectedValue == true 

Answer 3

要获得全部RuleId s所有条件均为真：

SELECT r.RuleID 
FROM Rule r 
    JOIN Conditional c 
    ON c.RuleId = r.RuleId 
    LEFT JOIN Input i 
    ON i.InputId = c.InputId 
GROUP BY r.RuleID 
HAVING COUNT(CASE WHEN (c.ExpectedValue=1) AND (i.InputId IS NOT NULL) 
        OR (c.ExpectedValue=0) AND (i.InputId IS NULL) 
        THEN 1 
        ELSE NULL 
       END) 
     = COUNT(*) 

另一种方式 - 可能会更慢，但它并不伤害测试速度。它不使用CASE但使用两个JOIN S，其中只有一个区别（EXCEPT）GROUP BY：

SELECT r.RuleID 
    FROM Rule r 
     JOIN Conditional c 
     ON c.RuleId = r.RuleId 
     LEFT JOIN Input i 
     ON i.InputId = c.InputId 
    WHERE c.ExpectedValue = 1 
    GROUP BY r.RuleID 
    HAVING COUNT(i.InputId) = COUNT(*) 
    EXCEPT 
    SELECT r.RuleID 
    FROM Rule r 
     JOIN Conditional c 
     ON c.RuleId = r.RuleId 
     JOIN Input i 
     ON i.InputId = c.InputId 
    WHERE c.ExpectedValue = 0