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我想要可视化过滤器的转换。我想绘制一个散点图,每隔半秒钟绘制下一个过滤器的值。'动画'2D散点图
我的目标是:
地块的所有值到点(K),但有值(K)的情节表示。
其中(k)和(k + 1)
叠加在全屏
绘制值之间暂停有情节办完所有迭代
我做了函数,但效率非常低,在绘制一些值之后,一切都会减慢。
我发现的唯一方法是使用交互式阴谋ion()
,每一步都用更新后的标记重新绘制所有点。对于每一个步骤(k),我想,而删除先前的点(K-1),并用不同的标记添加他们并添加当前点(K)
import pylab as pl
import time
xPos1 = pl.arange(100)
m1 = [pl.sin(pl.pi*x/10) for x in xPos1]
m2 = [pl.cos(pl.pi*x/30) for x in xPos1]
m3 = [pl.sin(pl.pi*x/20) for x in xPos1]
trueVal1 = [0 for real in xPos1]
def conversionAnim(xPos, trueVal, *args):
mTuple = [arg for arg in args]
colorList = ['Green','Blue','Orchid','Cyan','Goldenrod','Salmon','Orange','Violet','Magenta']
f = pl.figure(figsize =(17,8))
pl.ion()
pl.xlim(min(xPos)-1, max(xPos)+1)
pl.ylim(min(j for i in mTuple for j in i)-.5, max(j for i in mTuple for j in i)+.5)
for i in range(len(xPos)):
print '\ni = %i' % i
for j in range(len(mTuple)):
m = mTuple[j]
mVal = [element for element in m]
print 'Value%i is %s' %(j,mVal[i])
if i == 0:
pl.hold(True)
pl.scatter(xPos[i],mVal[i],s=50, marker = 'o', color = 'Dark'+colorList[j])
pl.plot(xPos[i],trueVal[i])
else:
pl.scatter(xPos[i],mVal[i],s=50, marker = 'o',color = 'Dark'+colorList[j])
pl.scatter(xPos[i-1], mVal[i-1],s=50, marker = 'o', color = 'white')
pl.scatter(xPos[i-1], mVal[i-1],s=50, marker = 'x', color = colorList[j])
pl.plot(xPos[i-1:i+1],trueVal[i-1:i+1], color = 'red')
pl.draw()
time.sleep(.01)
time.sleep(3) # to hold figure after its shown
if __name__ == '__main__':
conversionAnim(xPos1, trueVal1, m1, m2, m3)
我不知道怎么去解决ion()
并使此功能有效。
@cosmosis感谢您的评论。我最近问了几个问题,尽管最被接受,但其中一些仍然没有答案。这就是如何计算验收的方式。对此无能为力。 – tomasz74