提取物领域

Question

如果我有下面的代码中取出XML从数据库源，然后将它们转换成SimpleXMLElement对象数组：

try{ 
    function processLink($link , $appendArr){ 
    ## gets url from database as outlined above. 
     $xmlUrl = $link; 
     #Loads the url above into XML  
     $ConvertToXml = simplexml_load_file($xmlUrl); 
     # -> Setup XML 
     $appendArr[] = $ConvertToXml->channel->item; 
    } 
    #Connect to DB 
    require_once '../../src/conn/dbc.php'; 
    $dbconn = new PDO('mysql:host=localhost;port=3306;dbname=mydb',$db_user,$db_pass,array(PDO::ATTR_PERSISTENT => true)); 
    $q = $dbconn->prepare("SELECT FW_ArtSrcLink FROM FW_ArtSrc WHERE OneSet=:OneSet and leagID = :TheLeagueID"); 
    $q->execute(array(':OneSet' => 1, ':TheLeagueID' => 14)); # SET LEAGUE HERE. 
    $result = $q->fetchAll(); 
    $newsStory = array(); 

    foreach ($result as $value){ 
      if (is_array($value)){ 
       foreach ($value as $secondValue){ 
        processLink($secondValue , &$newsStory); 
       } 

       continue; 
     } 

     processLink($value , $newsStory); 

    }  
    ## Don't want to do this, I want to output just the [title] and [link]   
    //print_r($newsStory); 

} 

如果我只是想从SimpleXMLElement对象数组提取键：标题]和[链接]我如何用我目前的代码做到这一点？

我已经尝试使用：从print_r的

echo 'title'.$newStory->channel->item->title; 
echo 'title'.$newStory->title; 
echo 'title'.$value->title; 

输出（）：

所有与空值，或没有被回应的。如何输出标题和链接？

MODIFIED：

foreach ($newsStory as $story) { 
     echo "<hr>"."<a href='".$story->link."'>".$story->title."</a>"."<hr>"; 
    } 

The problem is... it prints some duplicates... how do I get ONLY unique links to display? 

修订FOREACH：

$stories = array(); // contains all of the stories already output 
    foreach ($newsStory as $story) { 
     if (! in_array($stories, $story->title)) { 
      $stories[] = $story->title; 
      echo "<hr>"."<a href='".$story->link."'>".$story->title."</a>"."<hr>";  
     } //if 
    } //foreach 

此输出警告（同时仍显示一式两份）：

Warning: in_array() expects parameter 2 to be array, object given on line 39: 

它基本上不喜欢这样的：

if (! in_array($stories, $story->title)) { 

Answer 1

您需要循环所产生的阵列到输出的每个项目，像这样：

<?php 
$stories = array(); // contains all of the stories already output 
foreach ($newsStory as $story) { 
    if (! in_array((string) $story->title, $stories)) { 
     $stories[] = (string) $story->title; 
     echo 'title'.$story->title; 
    } 
} 

更新：增加了代码检查，如果故事已经输出。