使用结果在不同的表

Question

如果我有这样的

table_1 

Field 1: victories 
Field 2: name 

table_2 

Field 1: name 
Field 2: birthday 

三个不同的表现在，我想要得到的人的生日最胜利。

所以我会做这样的事情（伪代码）：

select victories from table_1 and sum_it_all 
get name and pass name to table_2 
select birthday from table_2 where name 

好吧，这是很丑陋的伪代码，但我希望你明白了吧。

使用Andomar的解决方案工作正常。 现在我试图巢另一个表中它，这样虽然：

select address 
from table_3 
where birthday = 
    (
    select birthday 
    from table_2 
    where name = 
      (
      select name 
      from table_1 
      group by 
       name 
      order by 
       sum(victories) desc 
      limit 1 
      ) 
    ) 

我得到一个正确的答案，但因为某些原因也得到了null回来。我将如何输出胜利的总和？

Answer 1

select birthday 
from table_2 t2 
where name = 
     (
     select name 
     from table_1 t1 
     order by 
       victories desc 
     limit 1 
     ) 

如果一个用户可以在table_1有多行，你必须sum胜利：

select birthday 
from table_2 t2 
where name = 
     (
     select name 
     from table_1 t1 
     group by 
       name 
     order by 
       sum(victories) desc 
     limit 1 
     ) 

Answer 2

我想你要寻找的是这样的：

SELECT t2.name, SUM(t1.victories) as SumOfVictories, t2.birthday 
FROM table_1 as t1 
JOIN table_2 as t2 
ON table_1.name = table_2.name 
GROUP BY t2.name, t2.birthday 
ORDER BY SUM(t1.victories) DESC 
LIMIT 1 

Answer 3

想SELECT * FROM table_1 INNER JOIN table_2 ON table_1.name=table_2.name ORDER BY victories DESC会给你想要的结果吗？

Answer 4

试试这个：

Select name, birthday from table_2 t2 
     Join table_1 t1 On t1.Name = t2.name 
    Having Count(*) = 
     (Select Max(namCount) 
      From (Select Count(*) namCount 
       From table_1 
       Group By name)) 
    Group By t1.name 

Answer 5

您可以使用下面嵌套的SQL：

select name, birthday from table_2 where name in (
    select name from table_1 order by victories desc limit 1 
    ) 

Answer 6

这可能是你的问题的解决方案：

SELECT table_1.name, table_2.birthday 
FROM table_2 
JOIN table_1 ON table_1.name=table_2.name 
WHERE table_1.victories>=ALL(SELECT table_1.victories 
          FROM table_1)