4
我做了一个程序,用户用CenterX和CenterY坐标,宽度和高度创建两个自定义矩形。用户指定这些尺寸后,程序将显示一个矩形是否包含另一个矩形,与另一个矩形重叠,还是完全不符合。这里是我的代码:矩形重叠,但说它在里面?
import javafx.application.Application;
import javafx.scene.Scene;
import javafx.stage.Stage;
import javafx.scene.shape.*;
import javafx.scene.text.*;
import javafx.scene.paint.Color;
import javafx.scene.layout.Pane;
import java.util.*;
public class TwoRectangles extends Application
{
public void start(Stage stage)
{
Pane pane = new Pane();
Scanner input = new Scanner(System.in);
System.out.print("Enter the X and Y center coordinates for rectangle1: ");
double xCord1 = input.nextDouble();
double yCord1 = input.nextDouble();
System.out.print("Enter the Width and Height for rectangle1: ");
double width1 = input.nextDouble();
double height1 = input.nextDouble();
System.out.print("Enter the X and Y center coordinates for rectangle2: ");
double xCord2 = input.nextDouble();
double yCord2 = input.nextDouble();
System.out.print("Enter the Width and Height for rectangle2: ");
double width2 = input.nextDouble();
double height2 = input.nextDouble();
Rectangle rectangle1 = new Rectangle(xCord1, yCord1, width1, height1);
Rectangle rectangle2 = new Rectangle(xCord2, yCord2, width2, height2);
rectangle1.setFill(null);
rectangle2.setFill(null);
rectangle1.setStroke(Color.BLACK);
rectangle2.setStroke(Color.BLACK);
// Compute the 4 corners's coordinates for the rectangle
double r1x1 = xCord1 - (width1/2.0);
double r1x2 = xCord1 + (width1/2.0);
double r1y1 = yCord1 + (height1/2.0);
double r1y2 = yCord1 - (height1/2.0);
double r2x1 = xCord2 - (width2/2.0);
double r2x2 = xCord2 + (width2/2.0);
double r2y1 = yCord2 + (height2/2.0);
double r2y2 = yCord2 - (height2/2.0);
if ((r1x1 >= r2x1) && (r1x2 <= r2x2) && (r1y1 >= r2y1) && (r1y2 <= r2y2))
{
Text containText = new Text(500, 500, "One rectangle is contained in another");
pane.getChildren().add(containText);
}
else if ((r1x1 < r2x2) && (r1x2 > r2x1) && (r1y1 < r2y2) && (r1y2 > r2y1))
{
Text overlapText = new Text(500, 500, "The rectangles overlap");
pane.getChildren().add(overlapText);
}
else
{
Text noneText = new Text(500, 500, "The rectangles do not overlap");
pane.getChildren().add(noneText);
}
pane.getChildren().addAll(rectangle1, rectangle2);
Scene scene = new Scene(pane);
stage.setTitle("Overlapping Rectangles");
stage.setScene(scene);
stage.show();
}
}
每当我进入,(50,50)的centerX和centerY坐标两个矩形,宽度:20,为rectangle1高度50和宽度50,为rectangle2高度20它告诉我矩形在彼此内部而不是彼此重叠。我究竟做错了什么?
我要说的是,计算有错误'双r1y1 = yCord1 +(height1/2.0);'必须'双r1y1 = yCord1 - (height1/2.0);'和类似的'双r1y2 = yCord1 +(height1/2.0);'和r2y1和r2y2以及 – ItachiUchiha
@IchichiUchiha通常是的,但是当你绘画的东西,它可以更好另一种方法。 – maraca
@IchichiUchiha我把我的第一个条件改为你的条件,但我仍然得到相同的错误 – Bytes