PHP与命令行程序的交互

Question

我有一个特定的命令行程序，它接受来自流的输入而不是命令行参数（例如，一个使用scanf输入输入的C程序）我如何与此交互应用程序使用PHP？ exec（），shell_exec（）不会在这里帮助，因为输入不是通过命令行参数。我需要在PHP脚本和命令行程序之间建立一个连续的输入/输出连接，以便用户可以给PHP一个输入，哪个PHP将会中继到程序中，然后获取输出，然后显示给用户。

Answer 1

您可以使用proc_open。从该页面

例子：

<?php 
$descriptorspec = array(
    0 => array("pipe", "r"), // stdin is a pipe that the child will read from 
    1 => array("pipe", "w"), // stdout is a pipe that the child will write to 
    2 => array("file", "/tmp/error-output.txt", "a") // stderr is a file to write to 
); 

$cwd = '/tmp'; 
$env = array('some_option' => 'aeiou'); 

$process = proc_open('php', $descriptorspec, $pipes, $cwd, $env); 

if (is_resource($process)) { 
    // $pipes now looks like this: 
    // 0 => writeable handle connected to child stdin 
    // 1 => readable handle connected to child stdout 
    // Any error output will be appended to /tmp/error-output.txt 

    fwrite($pipes[0], '<?php print_r($_ENV); ?>'); 
    fclose($pipes[0]); 

    echo stream_get_contents($pipes[1]); 
    fclose($pipes[1]); 

    // It is important that you close any pipes before calling 
    // proc_close in order to avoid a deadlock 
    $return_value = proc_close($process); 

    echo "command returned $return_value\n"; 
} 
?> 

输出：

Array 
(
    [some_option] => aeiou 
    [PWD] => /tmp 
    [SHLVL] => 1 
    [_] => /usr/local/bin/php 
) 
command returned 0