我有几个函数,使用谷歌图表API实例化各种图表。
当我打电话给他们没有jQuery的$(document).ready
方法,一切工作正常。但用这种方法,我正在看空白屏幕。
为什么?
<script type="text/javascript" src = "http://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.js" charset="utf-8"></script>
<script type="text/javascript" src = "http://www.google.com/jsapi" charset="utf-8"></script>
function drawColumnChart1(){..some code..}
function drawColumnChart2(){..some code..}
function drawGeoChart(){.some code..}
//This works fine.
google.load("visualization", "1", {packages:["piechart", "corechart", "geomap"]});
google.setOnLoadCallback(window.drawColumnChart1);
google.setOnLoadCallback(window.drawColumnChart2);
google.setOnLoadCallback(window.drawGeoChart);
//This doesn't work
$(document).ready(function(){
google.load("visualization", "1", {packages:["piechart", "corechart", "geomap"]});
google.setOnLoadCallback(window.drawColumnChart1);
google.setOnLoadCallback(window.drawColumnChart2);
google.setOnLoadCallback(window.drawGeoChart);
});
UPDATE 以下是错误我在Firebug得到:
uncaught exception: [Exception... "Could not convert JavaScript argument" nsresult: "0x80570009 (NS_ERROR_XPC_BAD_CONVERT_JS)" location: "JS frame :: http://www.google.com/jsapi :: Q :: line 20" data: no]
http://www.google.com/jsapi
Line 22
显然$(document).ready在google对象可用之前发生,这就是为什么google.load在$(document).ready内部失败或类似的东西。好吧。 – Stann