更新SQL与甲骨文

Question

两个表我有这样的SQL

UPDATE A 
SET A.TEMSILCI_KOD = 4 
FROM S_MUSTERI A, S_TEKLIF B 
WHERE A.TEMSILCI_KOD = 9 
AND B.BAYI_KOD = 17 
AND A.HESAP_NO = B.HESAP_NO 

但我得到一个错误这样

Error starting at line 8 in command: 
UPDATE A 
SET A.TEMSILCI_KOD = 4 
FROM S_MUSTERI A, S_TEKLIF B 
WHERE A.TEMSILCI_KOD = 9 
AND B.BAYI_KOD = 17 
AND A.HESAP_NO = B.HESAP_NO 
Error at Command Line:9 Column:22 
Error report: 
SQL Error: ORA-00933: SQL command not properly ended 
00933. 00000 - "SQL command not properly ended" 
*Cause:  
*Action: 

哪里ERROR？

Answer 1

也许像

UPDATE S_MUSTERI 
SET TEMSILCI_KOD = 4 
WHERE TEMSILCI_KOD = 9 
AND EXISTS (SELECT 1 FROM S_TEKLIF B 
WHERE S_MUSTERI.HESAP_NO = B.HESAP_NO 
AND B.BAYI_KOD = 17) 

Answer 2

您的更新声明不遵循正确的语法。更新语句中没有from子句。它应该遵循以下格式

Update <table> 
    set <column> = <value> 
where <conditions> 

查看更新本文档： http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/statements_10007.htm#i2067715

Answer 3

在Oracle的语法来更新视图是从SQL * Server的语法不同。在Oracle中，你可以发出以下查询：

UPDATE (SELECT A.TEMSILCI_KOD 
      FROM S_MUSTERI A, S_TEKLIF B 
     WHERE A.TEMSILCI_KOD = 9 
      AND B.BAYI_KOD = 17 
      AND A.HESAP_NO = B.HESAP_NO) 
    SET TEMSILCI_KOD = 4 

注：这个查询只能在甲骨文工作，如果(S_TEKLIF.BAYI_KOD, S_TEKLIF.HESAP_NO)是唯一的（这样的更新将不会产生歧义和S_MUSTERI每行最多将更新一次） 。