如何去除Java字符串中的大括号？

Question

我的Java应用程序将会得到如下形式的字符串：

How now [[brown cow ]]. The arsonist [[ had oddly shaped ]] feet. The [[human torch was denied]] a bank loan. 

，需要一个正则表达式/方法，将剥离出的[[ ]]每个实例（和全包文本），从而把上面的字符串为：

How now. The arsonist feet. The a bank loan. 

声明保留的双空格（arsonist和feet，与和之间Thea之间）？这也很重要。

不确定这里的正则表达式是否合适，或者是否有更有效的方法剔除不需要的[[ ]]实例。

Answer 1

这是javascript。

var text = "How now [[brown cow ]]. The arsonist [[ had oddly shaped ]] feet. The [[human torch was denied]] a bank loan." 
text.replace(/\[\[[^\]]+\]\]/g, "") 

要匹配的正则表达式的括号将

/\[\[[^\]]+\]\]/g 

所以相当于Java将是

text.replaceAll("\[\[[^\]]+\]\]", ""); 

，并用一个空字符串

正则表达式，可以删除这两个更换双重和三重大括号

text.replaceAll("\[?\[\[[^\]]+\]\]\]?", "") 

Answer 2

这是replaceAll

str = str.replaceAll("\\[\\[[^\\]]*\\]\\]", ""); 

简单假设括号之间没有]。

Answer 3

尝试使用此代码：

public class Test{ 
public static void main(String[] args) { 
    String input = "How now [[brown cow ]]. The arsonist [[ had oddly shaped ]] feet. The [[human torch was denied]] a bank loan."; 
    // Will replace all data within braces [] 
    String replaceAll = input.replaceAll("(\\[.+?\\])|(\\])", ""); 
    System.out.println(replaceAll); 
} 

}

希望这有助于。

Answer 4

tring s = "How now [[brown cow ]]. The arsonist [[ had oddly shaped ]] feet. The [[human torch was denied]] a bank loan."; 

s=s.replaceAll("\\[.*?\\]","").replace("]",""); 

输出：

How now . The arsonist feet. The a bank loan.