我应该如何更改此代码以显示空白区域？

Question

请帮我更改此代码显示的项目，他们的数量= 0 ，也是我想的名字之间加空格和计数

$args = array('hide_empty=0'); 

$terms = get_terms('job_region', $args); 
if (!empty($terms) && !is_wp_error($terms)) { 
$count = count($terms); 
$i = 0; 
$term_list = '<ul class="statelist clearfix">'; 
foreach($terms as $term) { 
    $i++; 
    $term_list. = '<li count-all='.$term - > count. 
    '><a href="/job-search/?location='.$term - > name. 
    '&submit=true" title="'.esc_attr(sprintf(__('نمایش آگهی های %s', 'my_localization_domain'), $term - > name)). 
    '">'.$term - > name. 
    '('.$term - > count. 
    ')'. 
    '</a></li>'; 
    if ($count != $i) { 
     $term_list. = " "; 
    } else { 
     $term_list. = '</ul>'; 
    } 
} 
echo $term_list; 
} 

Answer 1

这应该做的伎俩为您提供： -

$terms = get_terms(array(
    'taxonomy' => 'job_region', 
    'hide_empty' => false, 
)); 

if (!empty($terms) && !is_wp_error($terms)) { 
$count = count($terms); 
$i = 0; 
$term_list = '<ul class="statelist clearfix">'; 
foreach($terms as $term) { 
    $i++; 
    $term_list. = '<li count-all='.$term - > count. 
    '><a href="/job-search/?location='.$term - > name. 
    '&submit=true" title="'.esc_attr(sprintf(__('نمایش آگهی های %s', 'my_localization_domain'), $term - > name)). 
    '">'.$term - > name. 
    ' ('.$term - > count. 
    ')'. 
    '</a></li>'; 
    if ($count != $i) { 
     $term_list. = " "; 
    } else { 
     $term_list. = '</ul>'; 
    } 
} 
echo $term_list; 
} 

您可以阅读更多@https://developer.wordpress.org/reference/functions/get_terms/