使用awk根据行和列名称在矩阵中打印索引值

Question

如何使用awk或其他函数以及第1行和第1列打印索引值？谢谢

> input 
name s1 s2 s3 s4 
g1 2 3 4 5 
g2 1 1 1 6 
g3 2 2 2 7 
g4 2 2 2 10 


> output 
g1 s1 2 
g2 s2 1 
g3 s3 2 
g4 s4 10 

Answer 1

用awk只打印矩阵

$ awk 'NR==1 { split($0,x); next } NF>=NR { print $1,x[NR],$NR }' matrix 
g1 s1 2 
g2 s2 1 
g3 s3 2 
g4 s4 10 

解释的主对角线值：

NR==1 { split($0,x);next } # split first record to array x for outputing s col 
NF>=NR {      # test for overflow if an asymmerical matrix 
    print $1,x[NR],$NR  # output 
} 

Answer 2

awk来救援！

假设输入文件是制表符分隔

awk -F'\t' 'NR==1{split($0,h);next} 
       {for(i=2;i<=NF;i++) print $1,h[i],$i}' file.tsv 

g1 s1 2 
g1 s2 3 
g1 s3 4 
g1 s4 5 
g2 s1 1 
g2 s2 1 
g2 s3 1 
g2 s4 6 
g3 s1 2 
g3 s2 2 
g3 s3 2 
g3 s4 7