字符串在python

我越来越有以下matter.Let的发言权麻烦匹配，我有两个列表中的某些字符串在词典：字符串在python

left        right 
british        7 
cuneate nucleus      Medulla oblongata 
Motoneurons       anterior

而且我有一个文件像下面的一些测试线：

<s id="69-7">British Meanwhile is the studio 7 album by british pop band 10cc 7.</s> 
<s id="5239778-2">Medulla oblongata,the name refers collectively to the cuneate nucleus and gracile nucleus, which are present at the junction between the spinal cord and the medulla oblongata.</s> 
<s id="21120-99">Terior horn cells, motoneurons located in the spinal.</s>

我想输出像下面的样子：

<s id="69-7"><w2>British</w2> Meanwhile is the studio <w2>7</w2> album by <w1>british</w1> pop band 10cc <w2>7</w2>.</s> 
<s id="5239778-2"><w2>Medulla oblongata</w2>,the name refers collectively to the <w1>cuneate nucleus</w1> and gracile nucleus, which are present at the junction between the spinal cord and the <w2>medulla oblongata</w2>.</s>

我试着用下面的代码：

import re 

def textReturn(left, right): 
    text = "" 
    filetext = open(text.xml, "r").read() 
    linelist = re.split(u'[\n|\r\n]+',filetext) 

    for i in linelist: 
     left = left.strip() 
     right = right.strip() 

     if left in i and right in i: 
      i1 = re.sub('(?i)(\s+)(%s)(\s+)'%left, '\\1<w1>\\2</w1>\\3', i) 
      i2 = re.sub('(?i)(\s+)(%s)(\s+)'%right, '\\1<w2>\\2</w2>\\3', i1) 
      text = text + i2 + "\n"   
    return text

但它给我：

'<s id="69-7">British meanwhile is the studio <w2>7</w2> album by <w1>British</w1> pop band 10cc 7.</s>'. 
<s id="5239778-2">Medulla oblongata,the name refers collectively to the <w1>cuneate nucleus</w1> and gracile nucleus, which are present at the junction between the spinal cord and the medulla oblongata.</s> 
<s id="21120-99">Terior horn cells, <w1>motoneurons</w2> located in the spinal.</s>

即如果有开头&端线，不能标记。

此外，我只是想得到返回这些行，其中匹配左&右字符串，而不是其他行。

任何解决方案，请！非常感谢！！！

来源

2011-07-31 Liza

该输入看起来像XML。你确定你不需要用XML解析器拉出字符串吗？此外，RE真的应该使用原始字符串（r'...'），因为它们不会专门处理反斜杠。 – Keith

Keith有一个好点。依靠整个'''元素在一条线上可能不是一个好主意。如果考虑字面字符串，CDATA部分，处理指令等，只能自己找到元素，但为什么当xml解析器已经为你做了这些工作？有一个学习曲线来使用它们，以及XSLT（用于按照你想要的方式修改文档），但它是如此值得！ –

它不会在开始和结束标记，因为您期望一个或多个空格前后关键字。可以使用\b（分词）。

附录

实际代码：

import re 

dict = [('british','7'),('cuneate nucleus','Medulla oblongata'),('Motoneurons','anterior')] 

filetext = """<s id="69-7">British Meanwhile is the studio 7 album by british pop band 10cc 7.</s> 
<s id="5239778-2">Medulla oblongata,the name refers collectively to the cuneate nucleus and gracile nucleus, which are present at the junction between the spinal cord and the medulla oblongata.</s> 
<s id="21120-99">Terior horn cells, motoneurons located in the spinal.</s> 
""" 

linelist = re.split(u'[\n|\r\n]+', filetext) 

s_tag = re.compile(r"(<s[^>]+>)(.*?)(</s>)") 

for i in range(3): 
    left, right = dict[i] 

    line_parts = re.search(s_tag, linelist[i]) 
    start = line_parts.group(1) 
    content = line_parts.group(2) 
    end = line_parts.group(3) 

    left_match = "(?i)\\b(%s)\\b" % left 
    right_match = "(?i)\\b(%s)\\b" % right 
    if re.search(left_match, content) and re.search(right_match, content): 
     line1 = re.sub(left_match, '<w1>\\1</w1>', content) 
     line2 = re.sub(right_match, '<w2>\\1</w2>', line1) 
     print(line_parts.group(1) + line2 + line_parts.group(3))

这是一个短期的解决方案的基础，但长期的，你应该尝试一下XML解析器方法。

来源

2011-07-31 18:21:47

问题仍然存在！ – Liza

好的，我会为你工作......另外我还会在'r'中添加一些字符串。给我10分钟左右。 –

提前致谢！ – Liza

如果你的输入文件将是一个XML文件，为什么不使用XML解析器？请参阅：19.5. xml.parsers.expat — Fast XML parsing using Expat

来源

2011-07-31 18:22:29 yasouser

字符串在python

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