使用基于Twisted的套接字限制聊天室中的用户数

Question

我遵循以下教程（http://www.raywenderlich.com/3932/how-to-create-a-socket-based-iphone-app-and-server），我得到了您可以在下面看到的代码。此代码允许无限数量的客户端连接到聊天。我想要做的就是限制这个客户端数量，以便不超过两个用户可以在同一个聊天室聊天。

为了做到这一点，我只需要知道一件事：如何为每个客户端获得唯一的标识符。以后可以在函数for c in self.factory.clients: c.message(msg)中使用它，以便仅将消息发送到我想要的客户端。

我会感谢任何贡献！

# Import from Twisted 
from twisted.internet.protocol import Factory, Protocol 
from twisted.internet import reactor 

# IphoneChat: our own protocol 
class IphoneChat(Protocol): 

    def connectionMade(self): 
     self.factory.clients.append(self) 
     print "Clients are ", self.factory.clients 

    def connectionLost(self, reason): 
     self.factory.clients.remove(self) 

    def dataReceived(self, data): 
     a = data.split(':') 
     print a 

     if len(a) > 1: 
      command = a[0] 
      content = a[1] 

      msg = "" 
      if command == "iam": 
       self.name = content 

      elif command == "msg": 
       msg = self.name + ": " + content 

       for c in self.factory.clients: 
        c.message(msg) 

    def message(self, message): 
     self.transport.write(message + '\n') 


# Factory: handles all the socket connections 
factory = Factory() 
factory.clients = [] 
factory.protocol = IphoneChat 

# Reactor: listens to factory 
reactor.listenTCP(80, factory) 
print "Iphone Chat server started" 
reactor.run(); 

Answer 1

试试这个：在connectionMade，如果客户数量已经是2，关闭新的连接：

if len(self.factory.clients) == 2: 
    self.transport.loseConnection()