2012-04-22 35 views
6

亲爱的同学的java程序员一个抽象类的工作, 我用从http://www.vogella.com/articles/JAXB/article.html如何使与JAXB

为JAXB XML使用一个例子我的3个班,UserStorage,用户和UserTest

它工作正常,但它只是在线程“主要” javax.xml.bind.UnmarshalException

JAXBContext context = JAXBContext.newInstance(UserStorage.class); 
       Marshaller m = context.createMarshaller(); 
       m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE); 

the User class is ABSTRACT!, so it throws an 

异常的unmarchialing:无法 创建instan用户 - 带有链接的异常:[com.un.InstantiationException] at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext.handleEvent(UnmarshallingContext.java:648) at com。 sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportError(Loader.java:236) at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext.createInstance(UnmarshallingContext.java :615) at com.sun.xml.internal.bind.v2.runtime.unmarshaller.StructureLoader.startElement(StructureLoader.java:170) at com.sun.xml.internal.bind.v2.runtime.unmarshaller .UnmarshallingContext._startElement(UnmarshallingContext.java:487) at com.sun .xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext.startElement(UnmarshallingContext.java:465) at com.sun.xml.internal.bind.v2.runtime.unmarshaller.SAXConnector.startElement(SAXConnector.java: 135) 在 com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.startElement(AbstractSAXParser.java:501) 在 com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.scanStartElement( XMLNSDocumentScannerImpl.java:400) 在 com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl $ FragmentContentDriver.next(XMLDocumentFragmentScannerImpl.java:2756) 在 com.sun.org.apache.xerces.internal。 impl.XMLDocumentScannerImpl.next(XMLDocumentScannerImpl.jav一:648) 在 com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(XMLNSDocumentScannerImpl.java:140) 在 com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl。 scanDocument(XMLDocumentFragmentScannerImpl.java:511) 在 com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:808) 在 com.sun.org.apache.xerces.internal。 parsers.XML11Configuration.parse在 com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:119)(XML11Configuration.java:737) 在 com.sun.org.apache。 xerces.internal.parsers.AbstractSAXParser.parse(AbstractSAXPars er.java:1205) at com.sun.org.apache.xerces.internal.jaxp.SAXParserImpl $ JAXPSAXParser.parse(SAXParserImpl.java:522) at com.sun.xml.internal.bind.v2。 runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:200) 在 com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal(UnmarshallerImpl.java:173) 在 javax.xml。 bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:137) 在 javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:194) 在platform.UserTest.main(UserTest.java:77)引起通过: java.lang。InstantiationException在 sun.reflect.InstantiationExceptionConstructorAccessorImpl.newInstance(InstantiationExceptionConstructorAccessorImpl.java:30) 在java.lang.reflect.Constructor.newInstance(Constructor.java:513) 在 com.sun.xml.internal.bind.v2。 ClassFactory.create0(ClassFactory.java:112) at com.sun.xml.internal.bind.v2.runtime.ClassBeanInfoImpl.createInstance(ClassBeanInfoImpl.java:231)at com.sun.xml.internal.bind.v2 .runtime.unmarshaller.UnmarshallingContext.createInstance(UnmarshallingContext.java:609) ...... 20多个

对此有任何解决方案,所以我可以将用户类绑定到XML,因为我可以用用户详细信息保存XML文件,但是当我想要检索它时,它会认为用户类是抽象的,我有管理员,经纪人,股东子类,但到目前为止,在我的用户测试课上,我只创建了4个管理员进行测试,感谢并希望您能提供帮助。

import platform.UserStorage; 
import platform.User; 



public class UserTest { 

private static final String USER_XML = "user2.xml"; 

public static void main(String[] args) throws JAXBException, IOException { 

    ArrayList<User> userList = new ArrayList<User>(); 

    // create test users 
      User user1 = new Admin(); 
      user1.setName("Dave"); 
      user1.setPass("1234"); 
      user1.setDeleted(true); 
      user1.setBan(false); 
      userList.add(user1); 

      User user2 = new Admin(); 
      user2.setName("James"); 
      user2.setPass("1234"); 
      user2.setDeleted(true); 
      user2.setBan(false); 
      userList.add(user2); 

      User user3 = new Admin(); 
      user3.setName("Mike"); 
      user3.setPass("1234"); 
      user3.setDeleted(true); 
      user3.setBan(false); 
      userList.add(user3); 


      // create bookstore, assigning book 
      UserStorage userstore = new UserStorage(); 
      userstore.setListName("Test List"); 
      userstore.setUserList(userList); 

      // create JAXB context and instantiate marshaller 
      JAXBContext context = JAXBContext.newInstance(UserStorage.class); 
      Marshaller m = context.createMarshaller(); 
      m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE); 
      m.marshal(userstore, System.out); 

      Writer w = null; 
      try { 
       w = new FileWriter(USER_XML); 
       m.marshal(userstore, w); 
      } finally { 
       try { 
        w.close(); 
       } catch (Exception e) { 
       } 
      } 

      // get variables from our xml file, created before 
      System.out.println(); 
      System.out.println("Output from our XML File: "); 
      Unmarshaller um = context.createUnmarshaller(); 
      UserStorage userstore2 = (UserStorage) um.unmarshal(new FileReader(
        USER_XML)); 

      for (int i = 0; i < userstore2.getUsersList().toArray().length; i++) { 
       System.out.println("User " + (i + 1) + ": " 
         + userstore2.getUsersList().get(i).getName() + " Pass " 
         + userstore2.getUsersList().get(i).getPass()); 
      }} } 



package platform; 


import javax.xml.bind.annotation.XmlElement; 
import javax.xml.bind.annotation.XmlRootElement; 
import javax.xml.bind.annotation.XmlType; 


//If you want you can define the order in which the fields are written 
//Optional 

/** 
* @author dinesh.kaushish, james.wyche //updated XML properties. 
* 
*/ 
@XmlRootElement(name = "user") 
@XmlType(propOrder = { "name", "pass", "deleted", "ban" }) 

..

public abstract class User implements UserInterface { 

private String name; 
private String pass; 
private boolean deleted; 
private boolean ban; 

/** 
* @ author dinesh.kaushish 
* @param String username 
* return void 
*/ 

public void setName(String name) 
{ 
    this.name = name; 
} 

// If you like the variable name, e.g. "name", you can easily change this 
    // name for your XML-Output: 

/** 
* @author dinesh.kaushish 
* @param null 
* @return String user; 
*/ 
@XmlElement(name = "user") 
public String getName() 
{ 
    return this.name; 
} 

/** 
* @author dinesh.kaushish 
* @param String pwd 
* @return void 
*/ 
public void setPass(String pass) 
{ 
    this.pass=pass; 
} 

/** 
* @author dinesh.kaushish 
* @param void 
* @return String password 
*/ 
@XmlElement(name = "pass") 
public String getPass() 
{ 
    return pass; 
} 

/** 
* @author dinesh.kaushish 
* @param dFlag 
* @return void 
*/ 
public void setDeleted(boolean deleted) 
{ 
    this.deleted = deleted; 
} 

/** 
* @author dinesh.kaushish 
* @return boolean isDeleted 
*/ 
@XmlElement(name = "deleted") 
public boolean getDeleted() 
{ 
    return deleted; 
} 


/** 
* @author dinesh.kaushish 
* @param bFlag 
*/ 
public void setBan(boolean ban) 
{ 
    this.ban = ban; 
} 

/** 
* @author dinesh.kaushish 
* @return Boolean isBanned 
*/ 
@XmlElement(name = "ban") 
public Boolean getBan() 
{ 
    return ban; 
} 


public abstract void addUser(); 
public abstract void removeUser(); 
public abstract void verifyUser(); 
public abstract void passReset(); 
public abstract void faultReport(); 
public abstract void RequestsForAccess(); 
public abstract void UpdateDetails(); 
public abstract void BanUser(); 
public abstract void ChangePermissions(); 


    } 



package platform; 

import java.io.FileInputStream; 
import java.io.FileNotFoundException; 
import java.util.HashMap; 

import javax.xml.stream.XMLEventReader; 
import javax.xml.stream.XMLInputFactory; 
import javax.xml.stream.XMLStreamException; 
import javax.xml.stream.events.XMLEvent; 

import java.util.ArrayList; 

import javax.xml.bind.annotation.XmlElement; 
import javax.xml.bind.annotation.XmlElementWrapper; 
import javax.xml.bind.annotation.XmlRootElement; 





/** 
* @author michael.wambeek, james.wyche //added JAXB support. 
* 
*/ 
//This statement means that class "Bookstore.java" is the root-element of our example 
@XmlRootElement(namespace = "platform") 
public class UserStorage { 

// XmLElementWrapper generates a wrapper element around XML representation 
    @XmlElementWrapper(name = "userList") 
    // XmlElement sets the name of the entities 
    @XmlElement(name = "user") 
private ArrayList<User> userList; 
private String listName = ""; 

//私有静态UserStorage实例; //结束james.wyche JAXB代码。

public UserStorage(){ 

} 

/** 
* @author michael.wambeek 
* 
* Searches for a username and returns the password. 
* 
* @param username The username to search for 
* @return The password of the correct username or null 
* @throws Exception 
*/ 
public String findUser(String username) throws Exception{ 
    return search(username); 
} 

public boolean storeUser(String username, String password, UserType type){ 
    return true; 
} 

/** 
* @author james.wyche 
* @param userList 
*/ 
public void setUserList(ArrayList<User> userList) { 
    this.userList = userList; 
} 

/** 
* 
* @return UserList 
*/ 
public ArrayList<User> getUsersList() { 
    return userList; 
} 

回答

0

这是行不通的,因为JAXB必须在解组xml的时候创建新类的实例(对象)。如果xml中的标签绑定到抽象类,它就不能实例化该类中的对象。您必须使User类为非抽象类型,或者将xml标签绑定到User的具体子类。

9

为什么这是失败的,因为Jaxb将尝试创建一个用户实例。这是抽象的,因此是失败的。

在您的抽象类中添加注释

@XmlTransient //Prevents the mapping of a JavaBean property/type to XML representation 
@XmlSeeAlso({Admin.class, <other class>}) //Instructs JAXB to also bind other classes when binding this class 

看到每个(XmlTransientXmlSeeAlso)的Javadoc

这将完成为防止JAXB从试图初始化抽象类。

我发现这种方法唯一的缺点是会有额外的名称空间信息添加到创建的XML中。

+2

的超类会清除可能不是所希望的继承关系添加XmlTransient,请参阅:http://blog.bdoughan.com/搜索/标签/ XmlTransient。丰满文章可能会有所帮助:http://blog.bdoughan.com/2010/11/jaxb-and-inheritance-using-xsitype.html – 2012-04-22 12:53:06

+0

谢谢,请看看 – Sean 2012-04-22 13:44:06

6

您需要添加一个XmlSeeAlso注释到具有属性Admin和User类的所有其他具体类的User类。

@XmlSeeAlso({Admin.class}) 

PS,别忘了将Xml标记@XmlRootElement添加到Admin类。

+1

非常感谢Noam,Jan和Sean,我修正了它使用你的解决方案:) – wyche5000 2012-04-22 13:27:20

0

您必须指定concrete类型每个元素:

<user xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="Admin"> 
    ... 
</user>