看看这对你的作品。这是基于我在这里给出的另一个答案。你循环的日子,每天积累与以前相同的价格在一个数组中。每当循环检测到价格变化时,就会创建一个新数组,等等。
<?php
$values[] = ["2017-09-01", "158.00"];
$values[] = ["2017-09-02", "158.00"];
$values[] = ["2017-09-03", "158.00"];
$values[] = ["2017-09-04", "158.00"];
$values[] = ["2017-09-10", "175.00"];
$values[] = ["2017-09-11", "175.00"];
$values[] = ["2017-10-20", "158.00"];
$values[] = ["2017-10-21", "158.00"];
$values[] = ["2017-10-22", "159.00"];
$values[] = ["2017-10-23", "152.00"];
$values[] = ["2017-10-24", "152.00"];
$ult = null;
$currentRange = [];
$ranges = [];
foreach ($values as $fecha) {
$day = $fecha[0];
$price = $fecha[1];
if ($ult === null) {
$currentRange = [
"price" => $price,
"days" => [$day]
];
}
else {
if ($price === $ult) {
$currentRange["days"][] = $day;
}
else {
$ranges[] = $currentRange;
$currentRange = [
"price" => $price,
"days" => [$day]
];
}
}
$ult = $price;
}
$ranges[] = $currentRange;
$rangesString = [];
foreach ($ranges as $range) {
$str = $range["days"][0];
if (count($range["days"]) > 1) {
$str .= " - ".$range["days"][count($range["days"]) - 1];
}
$str .= ": ".$range["price"];
$rangesString[] = $str;
}
echo (implode("<br>", $rangesString));
/* results:
2017-09-01 - 2017-09-04: 158.00
2017-09-10 - 2017-09-11: 175.00
2017-10-20 - 2017-10-21: 158.00
2017-10-22: 159.00
2017-10-23 - 2017-10-24: 152.00
*/
Demo
这是因为你想在下一次价格恢复到158一个新的日期对一个艰难的一个;所以在OP中你有三个结果,即使只有两个价格。你认为如何解析PHP中的结果? – BeetleJuice
事实上,即使在不同的年份,我也有更多相同的价格。 它仅用于打印出不同时期的价格,可能会在同一年重复,可能不会。 – Helenp